Reputation: 7176
I'm declaring a class like this:
#include "BindableInterface.h"
#include "../LuaHelper.h"
#include <map>
#include <string>
namespace utils{
class CLuaHelper;
};
namespace zel{
namespace utils{
class CAPIBindManager
{
typedef std::map<std::string, CBindeableInterface*> t_exposedClassMap;
t_exposedClassMap m_classesToExpose;
utils::CLuaHelper* m_luaHelper;
public:
bool exportClasses(const unsigned char* data);
bool executeLuaChunk(const std::string fileName, const std::string funtionName);
bool addClassToExpose(CBindeableInterface* bindableInterface, const std::string alias);
CAPIBindManager(void);
~CAPIBindManager(void);
};
};
};
But I got a compiling error that CLuaHelper is not a member of zel::utils. CLuaHelper is declared as utils::CLuaHelper (without zel) How do I need to declare this class. AFAIK, the forward declaration might solve this problem
Any ideas??
Upvotes: 0
Views: 118
Reputation: 91270
Use ::utils::CLuaHelper
to distinguish in between the two utils
namespaces.
Upvotes: 5