Reputation: 83
I'm calling a CL script from various places in the system. How do I get the file path of the script that is currently executed?
For example, the script source file is located in the /home/user/project/source/
directory. The script is being executed from the /home/user/
directory in the following manner:
user@machine:~$ ./project/source/script.lsp
Regardless of the callers location, script should know that it's located in the /home/user/project/source/
directory.
I've tried using the *default-pathname-defaults*
variable, but the following command shows the directory from which the script was called:
(format t "Pathname: ~S~&" *default-pathname-defaults*)
Environment: SBCL 1.4.5.debian on Ubuntu 18.04.
Upvotes: 3
Views: 390
Reputation: 11854
The *load-truename*
and *compile-file-truename*
variables are bound to the truename of the file being loaded with cl:load
or compiled with cl:compile-file
at the time of loading or compilation, respectively.
In your case, *load-truename*
is the thing to use. It will give a full, absolute pathname to the script.
Upvotes: 6
Reputation: 83
I stumbled upon one possible answer while browsing through different question.
As @Andrei has noted, it's possible to read the full pathname of the script which is invoked by using the following expression:
; truename function expands relative path to the script stored in $_ variable
(truename (sb-ext:posix-getenv "_"))
Since this solution is relying on $_
environment variable and bash shell, it may not be portable as @DmitryGrigoryev has noted in this answer at unix.stackexchange.com.
Upvotes: -1