CODEWITHSUNDEEP
c
rezzyrezz
rezzyrezz

Reputation: 21

Why doesn't this get characters?

Why does this for only runs 5 times? As in it gets 5 character and then stops. And if I change the i<10 to i<5 it only runs 3 times.

#include <stdio.h>

char a[1000];

int main()
{
    char a[100];
    for(int i=0;i<10;i++)
    {
        scanf("%c",&a[i]);
    }
}

Upvotes: 1

Views: 62

Answers (1)

Some programmer dude
Some programmer dude

Reputation: 409404

I think the problem is most likely that you don't think the Enter key will give you a character, but it will result in a newline '\n' character.

If you want to skip the newlines (or really any white-space) then use a leading space in the scanf format string:

scanf(" %c",&a[i]);
//     ^
// Note space here

If you want to read other space characters (like "normal" space or tab) then you need to use one of the character-reading functions like fgetc or getchar. For example as

for (size_t i = 0; i < 10; ++i)
{
    int c = getchar();
    if (c == '\n')
        continue;  // Skip newline
    if (c == EOF)
        break;  // Error or "end of file"

    // Use the character...
}

Upvotes: 5

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