Reputation: 7905
Let's say we have four properties :
ObjectProperty: superProp1
InverseOf: superProp3
ObjectProperty: prop1
InverseOf: prop2
SubPropertyOf:superProp1
ObjectProperty: prop2
InverseOf: prop1
ObjectProperty: superProp3
Pellet deduces that prop2
is a subproperty of superProp3
.
I can't understand this result.
Upvotes: 1
Views: 1093
Reputation: 11479
Assuming :a :prop2 :b
, one can infer that :a :superProp3 :b
(for any :a
and :b
):
Let's suppose that :a :prop2 :b
.
Then :b :prop1 :a
holds, because :prop2
is an inverse of :prop1
.
Then :b :superProp1 :a
holds, because :prop1
is a subproperty of :superProp1
.
Then :a :superProp3 :b
holds, because :superProp1
is an inverse of :superProp3
.
Slightly more formally:
T1. :a :prop1 :b <=> :b prop2 :a # :prop1 owl:inverseOf :prop2
T2. :a :prop1 :b => :a :superProp1 :b # :prop1 rdfs:subPropertyOf :superProp1
T3. :a :superProp1 :b <=> :b :superProp3 :a # :superProp1 owl:inverseOf :superProp3
A1. :a :prop2 :b # assumption, eliminated by T4
A2. :b :prop1 :a # A1, T1, modus ponens
A3. :b :superProp1 :a # A2, T2, modus ponens
A4. :a :superProp3 :b # A3, T3, modus ponens
T4. :a :prop2 :b => :a :superProp3 :b # A1, A4, deduction theorem; QED
More info:
Upvotes: 2
Reputation: 1581
Maybe using less abstract naming can give you a feeling of what's going on. Lets consider the same problem described using words having a semantic.
We know the following rules : Being Wet is the inverse of being Dry. It exist another kind of wetness, ReallyWet. Being ReallyWet always imply you're Wet, thus it is a subproperty of Wet. Finally, we also know that being ReallyWet is the opposite of being ReallyDry.
From this you -and pellet- can then conclude that ReallyDry is a kind of dryness.
Why ? The reasoning is : Dry is the inverde of Wet ReallyDry is the inverse of ReallyWet ReallyWet is a subproperty of Wet -> ReallyDry is the inverse of a subproperty of Wet, and as such is should be the subproperty of the inverse of Wet. Conclusion : ReallyWet is a subproperty of Wet.
Does it sound logic ? I think that pellet can explain the rule it used to deduce some triples.
It probably is :
( A inverse of B ) AND
( C inverse of D ) AND
(C is a sub property of A) ->
D is a sub property of B
Upvotes: 1