CODEWITHSUNDEEP
pythonprecision
Alex Mercer
Alex Mercer

Reputation: 19

Precision round off in Python

If some Python code's output is in format like "x.xx" How to increase its precision ?

eg:

import math

tc= int(input())
for i in range(0,tc):
    x1,y1,x2,y2,v1,v2= map(int,input().split())

    #distance
    # d = abs(math.sqrt( abs((x1-x2)*(x1-x2)) + abs((y1-y2)*(y1-y2)) ))

    #d1
    d1 = abs(math.sqrt( abs((x1-x1)*(x1-x2)) + abs((y1-0)*(y1-0)) ))


    #d2
    d2 = abs(math.sqrt( abs((x1-x2)*(x1-x2)) + abs((0-y2)*(0-y2)) ))


    niche = d1/v1
    upar = d2/v2

    roundoff = float("{:.5f}".format(niche+upar))
    print(roundoff)

its output is 5.5 make its output as 5.50000.

Upvotes: 1

Views: 67

Answers (1)

Jean-Didier
Jean-Didier

Reputation: 1977

print(roundoff) is pretty printing the float value. So you just need to remove the float conversion: 

roundoffstr = "{:.5f}".format(niche+upar)
print(roundoffstr)

Upvotes: 2

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