CODEWITHSUNDEEP
djangodjango-modelsdjango-templates
Siavash
Siavash

Reputation: 368

Passing Params to Django Model Methods

In a Django model passing a param to a method and using it in the code is easy.

Class Foo(models.Model):
    number = IntegerField()
    ...
    def bar(self, percent):
        return self.number * percent

f = Foo(number=250)
f.bar(10)

The question is how can this be done in the template layer? Somthing like : {{ foo.bar(10) }}

Upvotes: 3

Views: 308

Answers (3)

Yuji 'Tomita' Tomita
Yuji 'Tomita' Tomita

Reputation: 118458

Just do this calculation in the view, and not the template.

This is often the solution to many "template language can't do X" problems.

view

foo = Foo(number=250)
foo.bar = foo.bar(10) 
return direct_to_template(request, "foo.html", {'foo': foo})

template

{{ foo.bar }}

Upvotes: 0

Eli Courtwright
Eli Courtwright

Reputation: 192921

The simple answer is that you can't do this, which is by design; Django templates are designed to be keep you from writing real code in them. Instead, you'd have to write a custom filter, e.g.

@register.filter
def bar(foo, percent):
    return foo.bar( float(percent) )

This would let you make a call like {{ foo|bar:"250" }} which would be functionally identical to your (non-working example) of {{ foo.bar(250) }}.

Upvotes: 4

A Lee
A Lee

Reputation: 8066

By design, Django templates don't allow you to invoke methods directly so you'd have to create a custom template tag to do what you want.

Jinja2 templates do allow you to invoke methods, so you could look into integrating Jinja2 with Django as another option.

Upvotes: 1

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