Reputation: 360
I'm attempting to conditionally include or exclude a navigation property when querying Database using DbSet<T>
as follows:
var recordList = await dbContext.DbSet<T>
.Include(i => i.NavigationProp ?? null)
.AsNoTracking()
.ToListAsync();
I would like to exclude the Navigation property if it is null but include it when there is a value in the database. Any attempt to achieve this throws exception:
Message = "The Include property lambda expression 'i => (i.FeedbackImage ?? null)' is invalid. The expression should represent a property access: 't => t.MyProperty'. To target navigations declared on derived types, specify an explicitly typed lambda parameter of the....
Why does this .Include(i => i.NavigationProp ?? null)
fail when Include(Expression<Func<T, T>>)
method accepts an Expression?
Upvotes: 0
Views: 2605
Reputation: 89371
I'm trying to check if the Navigation property has a value, if true then it must be included else ignored.
So just
var recordList = await dbContext.DbSet<T>
.Include(i => i.NavigationProp)
.AsNoTracking()
.ToListAsync();
The Navigation Property will be loaded, unless the related Foreign Key value is null, in which case it will be Null.
Upvotes: 1
Reputation: 438
It fails because Include(Expression<Func<T, T>>)
gets actually translated to Include(string)
internally and eventually Include(string)
will need a property name and that's what the error is telling you, that's how entity framework is doing it.
Update:
Certainly not an elegant solution but you could try something like this:
Adding the navigation property as an interface to your models:
public interface IHasNavigationProperty
{
public NavigationProp NavigationProp { get; set; }
}
Models will implement it:
public class MyModel : IHasNavigationProperty
{
public NavigationProp NavigationProp { get; set; }
}
And a generic method that will check for that interface and execute the your include if the class implements it:
IList<T> GetRecords<T>() where T : class
{
var hasNavigationPropertyInterface = typeof(IHasNavigationProperty).IsAssignableFrom(typeof(T));
var query = _context.Set<T>().AsQueryable();
if (hasNavigationPropertyInterface)
{
var navigationPropertyName = nameof(NavigationProp);
query = query.Include(navigationPropertyName);
}
var recordList = query.AsNoTracking()
.ToList();
return recordList;
}
Update 2 :
Thinking about it you can just check for the property name instead of adding an interface:
private IList<T> GetRecords<T>() where T : class
{
var hasProperty = typeof(T).GetProperty(nameof(NavigationProp)) != null;
var query = _context.Set<T>().AsQueryable();
if (hasProperty)
{
var navigationPropertyName = nameof(NavigationProp);
query = query.Include(navigationPropertyName);
}
var recordList = query.AsNoTracking()
.ToList();
return recordList;
}
Upvotes: 1