Reputation: 161
I'm trying to add an input field on click of checkbox, and I want the checkbox to be checked (which is its default behaviour!), but the checkbox is not getting checked even after the input field appears. The following is my HTML code with JavaScript.
function check_test() {
if (document.contains(document.getElementById("test_input"))) {
document.getElementById("test_input").remove();
}
document.getElementById("test_div").innerHTML += "<input type='text' name='test_input' id='test_input'/>";
}
<div id="test_div">
<input type="checkbox" name="test_checkbox" id="test_checkbox" onclick="check_test()" />
</div>
I also tried this in JsFiddle which gives the same error and am not sure what I'm doing wrong.
https://jsfiddle.net/1yLb70og/1/
Upvotes: 3
Views: 4712
Reputation: 564
When use innerHTML all events of the element is canceled.
You need to use DOM functions.
<html>
<div id="test_div">
<input type="checkbox" name="test_checkbox" id="test_checkbox" onchange="check_test()" />
</div>
<script>
function check_test() {
var testdiv = document.getElementById("test_div");
if (!document.contains(document.getElementById("test_number"))) {
var newInput = document.createElement('input');
newInput.id = 'test_number';
testdiv.appendChild(newInput);
}else{
document.getElementById("test_number").remove();
}
}
</script>
</html>
related: https://stackoverflow.com/a/595825/5667488
Upvotes: 0
Reputation: 2536
You're conditionally removing the #test_input
if it exists in the DOM, but then you're not using an else
when adding it. So no matter which state you're in, you'll always end the function with having added the input to the DOM.
As others have mentioned, when you +=
on the innerHTML, then you're actually creating a whole new string, thereby reinitializing your original checkbox to unchecked.
You may want to just append a new child to the wrapper. I've also used the onchange
event instead so that it will do what you want no matter if the box is checked by a click or programmatically.
function check_test(checkbox) {
const checked = checkbox.checked; // is it checked?
const testInput = document.getElementById("test_input"); // test_input element
// if it's checked and doesn't have an input, add it
if (checked && !testInput) {
const newInput = document.createElement('input');
newInput.type = 'text';
newInput.name = 'test_input';
newInput.id = 'test_input';
checkbox.parentNode.appendChild(newInput);
}
// otherwise, if it's not checked and there is an input in the DOM, remove it
else if (!checked && testInput) {
document.getElementById("test_input").remove();
}
}
<div id="test_div">
<input type="checkbox" name="test_checkbox" id="test_checkbox" onchange="check_test(event.target)" />
</div>
Upvotes: 2
Reputation: 1
Try adding an event in the function declaration:
function check_test(e)
Then calling e.checked;
at the top or bottom of the function.
Let me know if that works. Answering from my phone so I can't test myself.
Upvotes: 0
Reputation: 366
You could use:
document.getElementById("test_div").insertAdjacentHTML("afterend", "<input type='text' name='test_input' id='test_input'/>");
Instead of:
document.getElementById("test_div").innerHTML += "<input type='text' name='test_input' id='test_input'/>";
Not the greatest solution; however, it works and it's extremely simple. Then you just fix up the rest of the page with CSS styling.
Upvotes: 0
Reputation: 6348
You're overwriting the content of the same div that the checkbox lives in, using innerHTML like that. Use a second div, or use create element and append child instead of replacing the entire contents.
This works.
<html>
<div id="test_div1">
<input type="checkbox" name="test_checkbox" id="test_checkbox" onclick="check_test()"/>
</div>
<div id="test_div"></div>
<script>
function check_test() {
if(document.contains(document.getElementById("test_number"))) {
document.getElementById("test_number").remove();
}
document.getElementById("test_div").innerHTML += "<input type='number' name='test_number' id='test_number'/>";
}
</script>
</html>
Upvotes: 3