CODEWITHSUNDEEP
javafunctionlambdafunctional-programming
spinos
spinos

Reputation: 31

Functional Programming exercise (Lambda function)

Happy new year everyone!

I have the following exercise for my Programming courses:

Write a class named Imbauba. Class must contain the following method:

A public method named dit which has a parameter (Function Float, Float type) named dawnward and returns Fuction Float, Float result. Lambda function which is returned must contain the value of dawnward divided by 67

   public class Imbauba {
        public Function<Float, Float> dit(Function<Float, Float> dawnward) {
             Function<Float, Float> sss = (a) -> dawnward / 67F;
             return sss;
        }
   }

This is what I've done so far. I have no clue how to continue. Can anyone guide me close to the solution? Thanks in advance

Upvotes: 1

Views: 103

Answers (1)

Tom Hawtin - tackline
Tom Hawtin - tackline

Reputation: 147124

You need to call the method on the Function. There is no funky syntaz to call the "function" of a functional interface. Something like:

         Function<Float, Float> sss = (a) -> dawnward.apply(a) / 67F;

@VLAZ mentions andThen in the comments. compose does the same thing in the opposite order. I think they are detrimental to readability, and are only really useful if it avoids creating another lambda expression (and even then I'd prefer not to bother).

Upvotes: 1

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