CODEWITHSUNDEEP
javahex
bird-dancer
bird-dancer

Reputation: 39

How can I add two Strings containing hexadecimal-numbers without converting them to int?

I have a hexadecimal number in a String which is too large to convert to int and long and want to add the value of another hexadecimal number. So let's say I have this number:

String hex1 = "0xf27f2029f9c103f77be78b9591c1ab27167858d27d789cd3ea8a270c67ea5d91";

And want to add:

int hex2 = 0x1;  or  String hex2 = "0x1";

I know this question has been asked allready How to subtract or add two hexadecimal value in java but the answers don't work for me because they all involve conversion to int.

Upvotes: 2

Views: 1220

Answers (2)

Shadmehr
Shadmehr

Reputation: 1

Change your code to:

String hex1="0xf27f2029f9c103f77be78b9591c1ab27167858d27d789cd3ea8a270c67ea5d91";
int hex2=0x1;
string hex2="0x1";

You need "" for entering a value for string.

Upvotes: -1

Arvind Kumar Avinash
Arvind Kumar Avinash

Reputation: 79085

You can do it as follows:

import java.math.BigInteger;

public class Main {
    public static void main(String[] args) {
        String hex1 = "0xf27f2029f9c103f77be78b9591c1ab27167858d27d789cd3ea8a270c67ea5d91";
        String hex2 = "0x1";
        System.out.println(
                "In decimal: " + new BigInteger(hex1.substring(2), 16).add(new BigInteger(hex2.substring(2), 16)));
        System.out.println("In hexdecimal: "
                + new BigInteger(hex1.substring(2), 16).add(new BigInteger(hex2.substring(2), 16)).toString(16));
    }
}

Output:

In decimal: 109684320921920394042076832992416841330182602685967688614501993994243850001810
In hexdecimal: f27f2029f9c103f77be78b9591c1ab27167858d27d789cd3ea8a270c67ea5d92

Upvotes: 2

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