Reputation: 38541
In the code below, I'd like the following behavior:
When the user clicks the button I've defined in App Mode, I want the print_async routine inside of it to be invoked, which waits for 2 seconds and then prints ""this is async print from buttonCLicked", then I want the print after which is "button clicked!" to appear. Instead what I get is an interpreter error:
Any help appreciated.
File "cell_name", line 6 SyntaxError: 'await' outside async function
from IPython.display import display
from ipywidgets import widgets
import asyncio
#DO NOT CHANGE THIS CELL
#Define an async function
async def print_async(message):
await asyncio.sleep(2)
print(message)
# Show that we can print from the top-level jupyter terminal
await print_async("This is a top-level async print")
#Define a callback function for the button
def onButtonClicked(_):
await print_async("this is async print from buttonCLicked")
print("button clicked!")
button = widgets.Button(
description='Click me',
disabled=False,
button_style='', # 'success', 'info', 'warning', 'danger' or ''
tooltip='Click me',
icon=''
)
button.on_click(onButtonClicked)
display(button)
button = widgets.Button(
description='Click me',
disabled=False,
button_style='', # 'success', 'info', 'warning', 'danger' or ''
tooltip='Click me',
icon=''
)
button.on_click(onButtonClicked)
display(button)
Goal: Get the button click to call the print_async method
Upvotes: 0
Views: 2414
Reputation: 1
First of all, You cannot use await keyword outside async function. If that is the entry point to your asynchronous program, use asyncio.run() function with function call as a parameter to run() method to call that co-routine.
Upvotes: 0
Reputation: 86433
You can do this with the asyncio.run
function (Requires Python 3.7 or newer):
In your code it would look like this:
def onButtonClicked(_):
asyncio.run(print_async("this is async print from buttonCLicked"))
print("button clicked!")
Upvotes: 1