Matheus Santos
Matheus Santos

Reputation: 85

Keep getting "undefined method `email' for nil:NilClass" what am I doing wrong?

So this is what my controller looks like. I want to click a button and have an email be sent to the email in the current quote. If I put a string email in there it works, but when I swap it to have a @quote.email grabbing the email from the current object it gives me this error:

"undefined method `email' for nil:NilClass"

I have no idea why this is doing this, someone please help!

class QuotesController < ApplicationController

  require 'sendgrid-ruby'
  include SendGrid

  before_action :set_quote, only: [:show, :edit, :update, :destroy]

  # GET /quotes
  # GET /quotes.json
  def index
    @quotes = Quote.all
  end

  def thankyoupage
  end

  # GET /quotes/1
  # GET /quotes/1.json
  def show
  end

  # GET /quotes/new
  def new
    @quote = Quote.new
  end

  # GET /quotes/1/edit
  def edit
  end

  # POST /quotes
  # POST /quotes.json
  def create

    @quote = Quote.new(quote_params)

    if @quote.save
      redirect_to thankyou_path
    else
      redirect_to root
    end

  end

  # PATCH/PUT /quotes/1
  # PATCH/PUT /quotes/1.json
  def update
    respond_to do |format|
      if @quote.update(quote_params)
        format.html { redirect_to @quote, notice: 'Quote was successfully updated.' }
        format.json { render :show, status: :ok, location: @quote }
      else
        format.html { render :edit }
        format.json { render json: @quote.errors, status: :unprocessable_entity }
      end
    end
  end

  # DELETE /quotes/1
  # DELETE /quotes/1.json
  def destroy
    @quote.destroy
    respond_to do |format|
      format.html { redirect_to quotes_url, notice: 'Quote was successfully destroyed.' }
      format.json { head :no_content }
    end
  end

  def sendQuoteEmail

    from = SendGrid::Email.new(email: '[email protected]')
    to = SendGrid::Email.new(email: @quote.email)
    subject = 'Sending with Twilio SendGrid is Fun'
    content = SendGrid::Content.new(type: 'text/plain', value: 'and easy to do anywhere, even with Ruby')
    mail = SendGrid::Mail.new(from, subject, to, content)

    sg = SendGrid::API.new(api_key: '*****************')
    response = sg.client.mail._('send').post(request_body: mail.to_json)
    puts response.status_code
    puts response.body
    puts response.headers

  end

  private
    # Use callbacks to share common setup or constraints between actions.
    def set_quote
      @quote = Quote.find(params[:id])
    end

    # Never trust parameters from the scary internet, only allow the white list through.
    def quote_params
      params.fetch(:quote, {}).permit(:first_name, :last_name, :phone_number, :address, :email, :quote_date, :quote_time, :quote_bedroom, :quote_bathroom, :quote_notes, :quote_price, :quote_price_recurring)
    end
end

When a Quote is created it has an email. I've created this button to run this action called SendQuoteEmail.

<%= button_to 'Send Quote Email', quotes_sendQuoteEmail_path, method: :post, class: 'btn btn-success mt-3' %>

What am I doing wrong? I keeps saying the @quote.email is NIL??

Upvotes: 1

Views: 155

Answers (2)

kiddorails
kiddorails

Reputation: 13014

Change your:

  before_action :set_quote, only: [:show, :edit, :update, :destroy]

to

  before_action :set_quote, only: [:show, :edit, :update, :destroy, : sendQuoteEmail]

This will let Rails run set_quote method which will enable controller to find @quote object before you act on it.

Add @quote in path helper:

<%= button_to 'Send Quote Email', quotes_sendQuoteEmail_path(@quote) ...

Upvotes: 1

Fernand
Fernand

Reputation: 1333

in your controller, update this line:

before_action :set_quote, only: [:show, :edit, :update, :destroy, :sendQuoteEmail]

then in your view, pass the id. quotes_sendQuoteEmail_path(:id => @quote.id)

<%= button_to 'Send Quote Email', quotes_sendQuoteEmail_path(:id => @quote.id), method: :post, class: 'btn btn-success mt-3' %>

Upvotes: 3

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