CODEWITHSUNDEEP
regexregex-negationregex-group
maxiy01
maxiy01

Reputation: 23

Regex: match anything but a group

I have text formatted like this:

(delimiter)
111111
(delimiter)
222222
(delimiter)
333333
(delimiter)

Where (delimiter) is a character group and 111111,222222,333333 - some random text, which does not include (delimiter) group.

Is there any way to write a regexp like "(delimiter) <anything,but a delimiter> (delimiter)"?

I expect capturing groups like this:

"(delimiter)
111111
(delimiter)",

"(delimiter)
222222
(delimiter)",

"(delimiter)
333333
(delimiter)"

More specifically, In my case delimiter is ([0-9]{1,2}[\s][A-z]+[\s][0-9]{4}[\s]) I tried to use negative lookahead like this:

(([0-9]{1,2}[\s][A-z]+[\s][0-9]{4}[\s])(?!([0-9]{1,2}[\s][A-z]+[\s][0-9]{4}[\s]))([0-9]{1,2}[\s][A-z]+[\s][0-9]{4}[\s]))

But that doesn't seem to work for me.

Upvotes: 2

Views: 216

Answers (1)

Barmar
Barmar

Reputation: 780949

You can use a regular expression as the delimiter in the string split() method. It will return all the values between the delimiters.

let string = `12 Dec 2019
111111
13 Dec 2019
222222
14 Dec 2019
333333
15 Dec 2019
`;

let result = string.split(/\s*[0-9]{1,2}\s[A-Z]+\s[0-9]{4}\s/i);
console.log(result);

I changed [A-z] to [A-Z] and add the i modifier to make it case-insensitive. There's also no need for [] around \s.

Upvotes: 1

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