Reputation: 587
I know there are thousands of articles and Q&A which teach me how to send an HTTP request in Java. But all of them use a BufferedReader to read the response from server.
I don't want to use a BufferedReader, because I encountered an "OutOfMemoryError" when using it on my android project. I don't know why this happened while others succeed, but it was certainly caused by BufferedReader after a long time of debugging and I am really tired of this issue. Is there any way to retrieve the response other than creating a new BufferedReader object? I just want to send a simplest get request, and get the response which provides HTML content,not considering efficiency.
Upvotes: 0
Views: 1090
Reputation: 60
You can use InputStream
E.g:
HttpURLConnection conn=(HttpURLConnection)(new URL(your URL).openConnection());
InputStream is=conn.getInputStream();
String str=new String(is.readAllBytes());
is.close();
return str;
Or Java 11 HttpClient
API.
E.g:
HttpClient client=HttpClient.newHttpClient();
HttpRequest request=HttpRequest.newBuilder().uri(new URI(your URL)).GET().build();
HttpResponse<String> response=client.send(request,BodyHandlers.ofString());
return response.body();
Upvotes: 0
Reputation: 763
You can use Volley for that. It's fast, fluid and lightweight.
In your build.gradle file, add this line and compile:
implementation 'com.android.volley:volley:1.1.1'
Make a network singleton
public class NetworkSingleton {
private static NetworkSingleton instance;
private RequestQueue requestQueue;
private ImageLoader imageLoader;
private static Context ctx;
private NetworkSingleton(Context context) {
ctx = context;
requestQueue = getRequestQueue();
imageLoader = new ImageLoader(requestQueue,
new ImageLoader.ImageCache() {
private final LruCache<String, Bitmap>
cache = new LruCache<String, Bitmap>(20);
@Override
public Bitmap getBitmap(String url) {
return cache.get(url);
}
@Override
public void putBitmap(String url, Bitmap bitmap) {
cache.put(url, bitmap);
}
});
}
public static synchronized NetworkSingleton getInstance(Context context) {
if (instance == null) {
instance = new NetworkSingleton(context);
}
return instance;
}
public RequestQueue getRequestQueue() {
if (requestQueue == null) {
// getApplicationContext() is key, it keeps you from leaking the
// Activity or BroadcastReceiver if someone passes one in.
requestQueue = Volley.newRequestQueue(ctx.getApplicationContext());
}
return requestQueue;
}
public <T> void addToRequestQueue(Request<T> req) {
getRequestQueue().add(req);
}
public ImageLoader getImageLoader() {
return imageLoader;
}
}
Make a String Request:
StringRequest stringRequest = new StringRequest(Request.Method.GET, "URL to fetch",
new Response.Listener<String>() {
@Override
public void onResponse(String response) {
//This is executed after successful response to URL
},
new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
//If error occurs
}
}) {
@Override
public Map<String, String> getHeaders() throws AuthFailureError {
Map<String, String> params = new HashMap<String, String>();
params.put("Authorization", "Add a header to request");
return params;
}
};
NetworkSingleton.getInstance(getApplicationContext()).addToRequestQueue(stringRequest);
Read more about volley at:
https://developer.android.com/training/volley
Upvotes: 1
Reputation: 847
Use OkHttp for efficient network access
What is OkHTTP? OkHTTP is an open source project designed to be an efficient HTTP client.
// avoid creating several instances, should be singleon
OkHttpClient client = new OkHttpClient();
Request request = new Request.Builder()
.url("https://www.vogella.com/index.html")
.build();
You can also add parameters
HttpUrl.Builder urlBuilder = HttpUrl.parse("https://api.github.help").newBuilder();
urlBuilder.addQueryParameter("v", "1.0");
urlBuilder.addQueryParameter("user", "vogella");
String url = urlBuilder.build().toString();
Request request = new Request.Builder()
.url(url)
.build();
source https://www.vogella.com/tutorials/JavaLibrary-OkHttp/article.html
Upvotes: 1