CODEWITHSUNDEEP
cconstants
pgp
pgp

Reputation: 83

int const array cannot be written to

Compiling the following program

int main(void) {
    int const c[2];
    c[0] = 0;
    c[1] = 1;
}

leads to error: assignment of read-only location ‘c[0]’. As I understand it, the const only applies to the location of c and so c[0] and c[1] should be mutable. Why is this error produced?

Upvotes: 2

Views: 73

Answers (1)

Blaze
Blaze

Reputation: 16876

As I understand it, the const only applies to the location of c

No. You can't modify the location of the array anyway. What you probably mean is if you have a int * const, then that indeed is a constant pointer to a modifiable int. However, int const c[2]; is an array of 2 constant ints. As such, you have to initialize them when you declare the array:

int const c[2] = {0, 1};

In constrast:

int main(void) {
    int c[2];
    int* const foo = c;
    foo[0] = 0;
    foo[0] = 1;
    //foo = malloc(sizeof(int)); doesn't work, can't modify foo, as it's constant
}

Upvotes: 8

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