CODEWITHSUNDEEP
pythonpython-3.xfile
annieinwonderland
annieinwonderland

Reputation: 31

find the longest word and the largest number in a text file

So im learning python right now and i really need your help. For example you do have random text file with words and numbers inside. You need to find the longest word and maximum number in this file. I managed to do the first half, i found the longest word:

def longest_word(word):
    with open(word, 'r') as infile:
        words = infile.read().split()
    max_len = len(max(words, key=len))
    return [word for word in words if len(word) == max_len]
print (("the longest word is :"), longest_word ('text.txt'))

can you help me with the second part? how to find maximum number in a file?

Upvotes: 2

Views: 419

Answers (4)

Daweo
Daweo

Reputation: 36390

As numbers are integers you might get them using str's method isdigit, consider following example:

words = ['abc', '123', 'xyz', '1', '999']
numbers = [i for i in words if i.isdigit()]
print(numbers)  # ['123', '1', '999']

then you might provide max with int as key following way:

print(max(numbers, key=int))  # 999

remember to NOT compare strs representing numbers as it might give surprising results, for example:

print(max(['9000','999']))  # 999

note that ValueError will occur if original list (words) do not contain any number.

Edit: I forget to note that above works solely for non-negative integers, to allow also negative one, you might write function for checking that as follow:

def represent_int(x):
    if not x:  # empty str
        return False
    if x[0] == '-':  # leading - that is negative integer
        return x[1:].isdigit()
    return x.isdigit()

and use it as follows:

numbers = [i for i in words if represent_int(i)]

note that I assume represent_int will be feeded solely with strs.

Upvotes: 0

Greg
Greg

Reputation: 1991

You're almost there! You can check each word to see if it's actually an integer, and then check if that value is greater than the previous max. This assumes the goal is to find the largest integer

for word in words:
    try:
        if int(word) > MAX_INT:
            MAX_INT = word
    except:
        pass

Upvotes: 1

Yoav Glazner
Yoav Glazner

Reputation: 8066

with open(word, 'r') as infile:
    data = infile.read()
    nums = [int(num) for num in re.findall('\d+', data)
    max_num = max(nums)

Upvotes: 0

Mayank
Mayank

Reputation: 158

You can implement error handling and try to parse the str as int: "2" --> 2

def longest_integer(word):
    max_int = 0
    with open(word, 'r') as infile:
        words = infile.read().split()
    for word in words:
        try:
            int_val = int(word)
            if int_val > max_int:
                max_int = int_val
        except:
            pass
    return max_int
print (("the longest integer is :"), longest_integer ('text.txt'))

Upvotes: 1

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