CODEWITHSUNDEEP
pythonhtmlflask
Lazloo Xp
Lazloo Xp

Reputation: 988

File not found by rendering a html using flask

I am pretty new in using flask and have a basic question: How to provide access to an HTML that is rendered using flask access to static files (such as images). Here my toy example:

I would like to render logo.svg on a website. The Project is structured as 

Project 
 |
 + -- static
      |
      + -- logo.svg
 + -- templates
      |
      + -- test.html
 + -- run_flask.py

test.html looks as follows

<!DOCTYPE>

<html>

    <head>

      <title>demo</title>

      <style>
        body {
          font-family: helvetica neue, helvetica, liberation sans, arial, sans-serif;
          font-size: 14px;
        }

      </style>
    </head>

    <body>
        <img src="./static/logo.svg" id="logo">
    </body>

</html>

and my run_flask-py script contains:

import flask
from flask import render_template, send_from_directory
from flask_cors import CORS

app = flask.Flask(__name__, static_url_path='')
CORS(app)
app.config["DEBUG"] = True

@app.route('/<string:page_name>/')
def render_static(page_name):
    return render_template('%s.html' % page_name)

app.run(port=5001)

When a now run the script, the console output is:

Running on http://127.0.0.1:5001/ (Press CTRL+C to quit)

So far so good, but in chrome, http://127.0.0.1:5001/test/ looks like:

enter image description here

I already looked at How to serve static files in Flask as the problem sounds similar. But I am actually completed confused about how the suggested send_from_directory can help me here.

Can somebody help?

Upvotes: 1

Views: 2572

Answers (2)

Debangshu Paul
Debangshu Paul

Reputation: 344

try with 

<img src="../static/logo.svg" id="logo">

instead of

<img src="./static/logo.svg" id="logo">

the .. points it to the parent directory and the /static enters into the static directory.

Upvotes: 0

v25
v25

Reputation: 7621

You ought to remove the static_url_path argument when you initialise the app:

app = flask.Flask(__name__)

By default flask will look in the subdirectory static/ for any static files. Your directory structure meets this requirement.

As @roganjosh comments, this should then work in the template with:

<img src="{{ url_for('static', filename='logo.svg') }}" id="logo">

As a debug step, you could load http://127.0.0.1:5001/static/logo.svg in the browser, and this should display correctly.

UPDATE: re. comment

So I guess an empty string defaults to the current app directory or would you need / for that

Always good to investigate the actual source code:

:param static_url_path: can be used to specify a different path for the
                        static files on the web.  Defaults to the name
                        of the `static_folder` folder.
:param static_folder: the folder with static files that should be served
                      at `static_url_path`.  Defaults to the ``'static'``
                      folder in the root path of the application.

What you were probably looking for was static_folder which controls the server based directory. static_url_path effects the URL path which static files are available on the frontend.

Definately easier to just stick with the defaults here, and define neither.

Upvotes: 1

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