Reputation: 37
I am trying to remove unnecessary whitespace from my char* for future use. Basically, I want to only have one space between words and remove any additional spaces, tabs, or new line characters in between words. The current code I have almost works I believe, but I am unable to read the memory of the individual characters I am storing in my array. Also any solution must not have a maximum character size so if dynamic memory allocation is needed that would need to be considered as well. Is there a way to get this working? Thanks
EDIT 1: trailing and leading spaces should also be removed. Thanks to @Vlad from Moscow for the clarification
int main()
{
char* fileString1;
fileString1=removeAdditionalWhiteSpace(fileString1);
}
char* removeAdditionalWhiteSpace(char* wordList)
{
char characterHolder;
char* finalList[strlen(wordList)];
char* delimeter = wordList;
int i = 0;
do
{
finalList[i] += characterHolder;
char* hasSpace = NULL;
while (*delimeter == ' ' || *delimeter == '\n' || *delimeter == '\t')
{
if(*delimeter == ' ')
{
if(hasSpace==NULL)
{
hasSpace = delimeter;
characterHolder = *delimeter;
}
else
{
++delimeter;
}
}
else if(*delimeter == '\n' || *delimeter == '\t')
{
*delimeter = ' ';
if(hasSpace==NULL)
{
hasSpace = delimeter;
characterHolder = *delimeter;
}
else
{
++delimeter;
}
}
}
hasSpace=NULL;
characterHolder = *delimeter;
i++;
}
while( (*wordList++ = *delimeter++) );
return *finalList;
}
Upvotes: 1
Views: 243
Reputation: 44240
Minimalistic approach:
size_t delspaces(char * str)
{
size_t src, dst;
size_t cnt;
for (cnt=src=dst=0; str[dst] = str[src++]; ) {
if (isspace(str[dst])) {
if (dst && !cnt++) str[dst++] = ' '
continue;
}
cnt=0;
dst++;
}
// remove trailing spaces
while (dst && isspace(str[dst-1])) str[--dst] = 0;
// return the string length of the resulting string
// (which could be useful for the caller)
return dst;
}
Final note: the last while()
could be an if()
, since there can be only one trailig space.
Upvotes: 0
Reputation: 64682
Man that looks super complicated.
Here's a simple function to remove whitespace from the string:" This is a test \t of some \n Extra white space. "
#include <stdio.h>
#include <ctype.h>
void removeWS(char* text)
{
char* d = text;
while (isspace(*text)) ++text;
while(*text)
{
*d = isspace(*text)? ' ' : *text;
text++;
while (isspace(*d) && isspace(*text)) ++text;
if (*text) d++;
}
*d = *text;
}
int main(void) {
char text[] = " This is a test \t of some \n Extra white space. ";
removeWS(text);
printf("%s\n", text);
return 0;
}
Success #stdin #stdout 0s 4284KB
This is a test of some Extra white space.
Upvotes: 0
Reputation: 310940
Your function does not make sense and has undefined behavior.
For example the variable characterHolder
was not initialized and it is added to pointer finalList[i]
char characterHolder; // <===
char* finalList[strlen(wordList)];
char* delimeter = wordList;
int i = 0;
do
{
finalList[i] += characterHolder; // <===
//….
If you need to remove redundant white spaces from a string including its leading and trailing white spaces then the function can look as it is shown in the demonstrative program below.
#include <stdio.h>
#include <ctype.h>
char * remove_duplicate_spaces( char *s )
{
char *src = s, *dsn = s;
while ( isspace( ( unsigned char )*src ) ) ++src;
do
{
char c = *src;
if ( isspace( ( unsigned char )c ) ) c = ' ';
if ( c == ' ' )
{
while ( isspace( ( unsigned char ) *++src ) );
if ( *src )
{
*dsn++ = c;
}
}
*dsn++ = *src;
} while ( *src++ );
return s;
}
int main(void)
{
char s[] = "\t\tIt is\t\ta very\nlong\nstring.\t\t";
printf( "\"%s\"\n", s );
printf( "\"%s\"\n", remove_duplicate_spaces( s ) );
return 0;
}
Its output is
" It is a very
long
string. "
"It is a very long string."
Upvotes: 1