Reputation: 51
I have a problem with displaying images in carousel. I want to display 2 images per carousel slide. I took images from database using while loop to create slides. The problem is that with my code it only displays one image per slide.
This is how it looks now: Check the image
<?php
$brojacPoStrani = 0;
$sqlIzvestaji = mysqli_query($con, "SELECT operacije.nazivEng, izvestaji.operacija, izvestaji.ucinak, izvestaji.id FROM izvestaji INNER JOIN operacije ON izvestaji.operacijaId=operacije.id WHERE projekatId='$projekatId' AND datum='$datum'");
while ($row = mysqli_fetch_array($sqlIzvestaji)) {
$id = $row['id'];
$sqlSlike = mysqli_query($con, "SELECT img_name FROM slike WHERE izvestajId='$id' AND datum='$datum'");
$brojacDuplikata = false;
while ($row2 = mysqli_fetch_array($sqlSlike)) {
if ($brojacPoStrani % 2 == 0) {
?>
<div class="carousel-cell" style="background-image: url('img/izvestaji.jpg'); background-repeat: no-repeat; background-size: 100% 350px;">
<h1 style="color: #fff; text-align: left; padding-left: 15px; font-weight: bold;"><?php echo $row['nazivEng']; ?></h1>
<?php
if ($brojacDuplikata === false) {
$brojacDuplikata = true;
?>
<p style="text-align: left; padding-left: 45px; padding-top: 20px; padding-bottom: 10px;"><?php echo $row['operacija'] . " - " . $row['ucinak']; ?></p>
<?php
} else {
?>
<p style="text-align: left; padding-left: 45px; padding-top: 40px; padding-bottom: 10px;"></p>
<?php
}
?>
<div class="row">
<?php
if ($brojacPoStrani % 2 == 0) {
?>
<div class="col-lg-6">
<img src="../files/izvestaji/<?php echo $project; ?>/<?php echo $datum; ?>/<?php echo $row['nazivEng']; ?>/<?php echo $row2['img_name']; ?>" style="width: 350px; height: 350px; padding-left: 10px;" class="float-right" />
</div>
<?php
} else {
?>
<div class="col-lg-6">
<img src="../files/izvestaji/<?php echo $project; ?>/<?php echo $datum; ?>/<?php echo $row['nazivEng']; ?>/<?php echo $row2['img_name']; ?>" style="width: 350px; height: 350px; padding-right: 10px;" class="float-left" />
</div>
<?php
}
?>
</div>
<br />
</div>
<?php
}
$brojacPoStrani++;
}
$brojacPoStrani = 0;
}
Upvotes: 1
Views: 965
Reputation: 33823
As mentioned it looks like you should be able to use a single query rather than having nested queries - and to display 2 images per carousel slide
you effectively want to select data from the current and next rows. One easy way to do that would be to assign the entire recordset to a variable and then process that array using a for
loop. The following is a simplified, semi-pseudo code version that attempts to combine the sql queries and assign recordset to an array. It is not tested as such but it might? be of use.
$sql="select
o.naziveng,
i.operacija,
i.ucinak,
i.id,
s.img_name
from izvestaji i
inner join operacije o on i.operacijaid=o.id
inner join slike s on s.izvestajId=i.id
where projekatid='$projekatid' and datum='$datum'";
$res = mysqli_query( $con, $sql );
if( $res ){
$arr = mysqli_fetch_all( $res, MYSQLI_BOTH );
for( $i=0; $i < count( $arr ); $i+=2 ){
try{
$r1=array_key_exists( $i+0, $arr ) ? $arr[ $i+0 ] : false;
$r2=array_key_exists( $i+1, $arr ) ? $arr[ $i+1 ] : false;
/*
generate the HTML structure and add two images
*/
echo '<div class="carousel-cell">'; # simplified version
if( $r1 )echo 'row 1: '.$r1['img_name'];
if( $r2 )echo 'row 2: '.$r2['img_name'];
echo '</div>';
}catch( Exception $e ){
continue;
}
}
}
Upvotes: 1