CODEWITHSUNDEEP
javascriptjquery
dontbannedmeagain
dontbannedmeagain

Reputation: 480

JavaScript splice more than 1 value?

How to splice the string value so the output only become 'LA1','LA4'. I tried the method below but it still gave me string_2 output.

var string_1 = 'LA2,LA3'
var string_2 = "LA1,LA2,LA3,LA4";

var unique_1 = string_1.split(',');
var unique_2 = string_2.split(',');

const index = unique_2.indexOf(unique_1);
if (index > -1) {
  unique_2.splice(index, 1);
}
console.log(unique_2);

Upvotes: 0

Views: 70

Answers (3)

Mark
Mark

Reputation: 92440

Instead of using splice() You can filter() with includes().

var string_1 = 'LA2,LA3'
var string_2 = "LA1,LA2,LA3,LA4";

var unique_1 = string_1.split(',');
var unique_2 = string_2.split(',');

var filtered = unique_2.filter(s => !unique_1.includes(s))

console.log(filtered);

If your lists are very large, you might want to use something other than an array with includes() such as a Set that offers constant time lookups.

Upvotes: 1

Christian Carrillo
Christian Carrillo

Reputation: 2761

using reduce:

var string_1 = 'LA2,LA3'
var string_2 = "LA1,LA2,LA3,LA4";

var unique_1 = string_1.split(',');
var unique_2 = string_2.split(',');

const result = unique_2.reduce((acc, item) => {
  !string_1.includes(item) && acc.push(item)
  return acc
}, [])

console.log(result)

Upvotes: 0

Ever Dev
Ever Dev

Reputation: 2142

Array.prototype.indexOf() only finds one element and can not find an array. To get the expected value, you can do as follows.

var string_1 = 'LA2,LA3'
var string_2 = "LA1,LA2,LA3,LA4";

var unique_1 = string_1.split(',');
var unique_2 = string_2.split(',');

unique_2 = unique_2.filter(item => !unique_1.includes(item));

console.log(unique_2);

Upvotes: 0

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