CODEWITHSUNDEEP
java
suter
suter

Reputation: 3375

How to convert Set<String> to String[]?

I need to get a String[] out of a Set<String>, but I don't know how to do it. The following fails:

Map<String, ?> myMap = gpxlist.getAll();
Set<String> myset = myMap.keySet();
String[] GPXFILES1 = (String[]) myset.toArray(); // Here it fails.

How can I fix it so that it works?

Upvotes: 316

Views: 315910

Answers (7)

BalusC
BalusC

Reputation: 1108732

Use the Set#toArray(IntFunction<T[]>) method taking an IntFunction as generator.

String[] GPXFILES1 = myset.toArray(String[]::new);

If you're not on Java 11 yet, then use the Set#toArray(T[]) method taking a typed array argument of the same size.

String[] GPXFILES1 = myset.toArray(new String[myset.size()]);

While still not on Java 11, and you can't guarantee that myset is unmodifiable at the moment of conversion to array, then better specify an empty typed array.

String[] GPXFILES1 = myset.toArray(new String[0]);

Upvotes: 514

akhil_mittal
akhil_mittal

Reputation: 24157

Java 11

The new default toArray method in Collection interface allows the elements of the collection to be transferred to a newly created array of the desired runtime type. It takes IntFunction<T[]> generator as argument and can be used as:

 String[] array = set.toArray(String[]::new);

There is already a similar method Collection.toArray(T[]) and this addition means we no longer be able to pass null as argument because in that case reference to the method would be ambiguous. But it is still okay since both methods throw a NPE anyways.

Java 8

In Java 8 we can use streams API:

String[] array = set.stream().toArray(String[]::new);

We can also make use of the overloaded version of toArray() which takes IntFunction<A[]> generator as:

String[] array = set.stream().toArray(n -> new String[n]);

The purpose of the generator function here is to take an integer (size of desired array) and produce an array of desired size. I personally prefer the former approach using method reference than the later one using lambda expression.

Upvotes: 69

user10763303
user10763303

Reputation: 

Set<String> stringSet= new HashSet<>();
String[] s = (String[])stringSet.toArray();

Upvotes: 2

Rafal Borowiec
Rafal Borowiec

Reputation: 5244

In Java 11 we can use Collection.toArray(generator) method. The following code will create a new array of String:

Set<String> set = Set.of("one", "two", "three");
String[] array = set.toArray(String[]::new)

See: https://docs.oracle.com/en/java/javase/11/docs/api/java.base/java/util/Collection.html#toArray(java.util.function.IntFunction)

Upvotes: 3

Jo&#227;o Vitor Veronese Vieira
Jo&#227;o Vitor Veronese Vieira

Reputation: 351

I was facing the same situation.

I begin by declaring the structures I need:

Set<String> myKeysInSet = null; String[] myArrayOfString = null;

In my case, I have a JSON object and I need all the keys in this JSON to be stored in an array of strings. Using the GSON library, I use JSON.keySet() to get the keys and move to my Set :

myKeysInSet = json_any.keySet();

With this, I have a Set structure with all the keys, as I needed it. So I just need to the values to my Array of Strings. See the code below:

myArrayOfString = myKeysInSet.toArray(new String[myKeysInSet.size()]);

This was my first answer in StackOverflow. Sorry for any error :D

Upvotes: 0

user7708
user7708

Reputation: 131

Guava style:

Set<String> myset = myMap.keySet();
FluentIterable.from(mySet).toArray(String.class);

more info: https://google.github.io/guava/releases/19.0/api/docs/com/google/common/collect/FluentIterable.html

Upvotes: 5

d1e
d1e

Reputation: 6442

Use toArray(T[] a) method:

String[] array = set.toArray(new String[0]);

Upvotes: 44

Related Questions