Reputation: 3139
In the following code, if the signal errorHappened
is emitted from the main thread it works without problem. However if it is emitted from the QThread
thread it fails with the following error:
QObject::connect: Cannot queue arguments of type 'ErrorCode'
(Make sure 'ErrorCode' is registered using qRegisterMetaType().)
Is there a way that the signal can be successfully emitted from the QThread
thread? If so, how?
MyClass.h
#import <QThread>
#import <atomic>
class MyClass : public QThread
{
Q_OBJECT
public:
explicit MyClass(QObject *parent = Q_NULLPTR);
virtual ~MyClass() override;
enum ErrorCode {
ErrorA,
ErrorB,
ErrorC
};
Q_ENUM(ErrorCode)
signals:
void errorHappened(ErrorCode errorCode);
public slots:
void mainThreadError();
void otherThreadError();
private:
std::atomic<bool> m_running;
std::atomic<bool> m_signalStop;
std::atomic<bool> m_signalError;
void run() override;
void stop();
};
MyClass.cpp
#include "MyClass.h"
MyClass::MyClass(QObject *parent)
: QThread(parent)
{
start();
}
MyClass::~MyClass()
{
stop();
}
void MyClass::mainThreadError()
{
emit errorHappened(ErrorCode::ErrorA);
}
void MyClass::otherThreadError()
{
m_signalError = true;
}
void MyClass::run()
{
m_running = true;
while (!m_signalStop) {
if (m_signalError) {
emit errorHappened(ErrorCode::ErrorA);
m_signalError = false;
}
msleep(1);
}
m_running = false;
m_signalStop = false;
}
void MyClass::stop()
{
if (m_running) {
m_signalStop = true;
wait();
}
}
main.cpp
#include <QGuiApplication>
#include <QQuickView>
#include "MyClass.h"
int main(int argc, char *argv[])
{
QGuiApplication app(argc, argv);
QQuickView *view = new QQuickView();
qmlRegisterType<MyClass>("MyClass", 1, 0, "MyClass");
view->setSource((QUrl(QStringLiteral("qrc:/main.qml"))));
view->create();
view->show();
return app.exec();
}
main.qml
import QtQuick 2.12
import QtQuick.Controls 2.5
import MyClass 1.0
Rectangle {
id: root
width: 800
height: 600
focus: true
MyClass {
id: tester
onErrorHappened: {
var s
switch (errorCode) {
case MyClass.ErrorA:
s = "Error A happened"
break
}
console.log(s)
}
}
Row {
spacing: 30
Button {
id: mainThreadButton
enabled: !tester.testRunning
text: "Test on main thread"
onClicked: tester.mainThreadError()
}
Button {
id: otherThreadButton
enabled: !tester.testRunning
text: "Test on other thread"
onClicked: tester.otherThreadError()
}
}
}
Upvotes: 1
Views: 349
Reputation: 244132
qmlRegisterType makes the QObject (MyClass) class accessible in QML (Q_PROPERTY, Q_ENUM, Q_SIGNAL, Q_SLOT, Q_INVOKABLE, etc.) but does not allow the transmission of data between threads, for this case it must be registered using qRegisterMetaType<MyClass::ErrorCode>("ErrorCode")
:
main.cpp
#include <QGuiApplication>
#include <QQuickView>
#include "MyClass.h"
static void registerTypes(){
qRegisterMetaType<MyClass::ErrorCode>("ErrorCode");
qmlRegisterType<MyClass>("MyClass", 1, 0, "MyClass");
}
Q_COREAPP_STARTUP_FUNCTION(registerTypes)
int main(int argc, char *argv[])
{
QGuiApplication app(argc, argv);
QQuickView view;
view.setSource((QUrl(QStringLiteral("qrc:/main.qml"))));
view.show();
return app.exec();
}
Upvotes: 1
Reputation: 101
your type "ErrorCode" defined only in thread (not in main)
For user defined types you can use (read this https://doc.qt.io/qt-5/qmetatype.html)
Q_DECLARE_METATYPE(ErrorCode);
Use standard types for arguments (int,QMap,QString....)
Upvotes: 0