Reputation: 35
EN = 10;
etable = [1,2,3,4,5,6;
4,5,6,7,8,9;
7,8,9,10,11,12;
10,11,12,13,14,15;
13,14,15,16,17,18;
16,17,18,19,20,21;
19,20,21,22,23,24;
22,23,24,25,26,27;
25,26,27,28,29,30;
28,29,30,31,32,33];
Is it possible to make a for loop in which I just change the EN
value and it automatically creates etable
? Because I have to make EN
50 so it'll not be good to write 50 lines in etable
.
I tried in this way:
EN = 10;
c = 1:EN;
nodes = zeros(size(c',1),2);
for i = 1:length(c)
nodes(i,1) = i;
nodes(i,2) = i+1;
end
etable = zeros(size(c',1),6);
for i = 1:size(nodes,1)
etable(i,1) = 2*nodes(i,1)-1;
etable(i,2) = 2*nodes(i,1);
etable(i,3) = 2*nodes(i,1)+1;
etable(i,4) = 2*nodes(i,2);
etable(i,5) = 2*nodes(i,2)+1;
etable(i,6) = 2*nodes(i,2)+2;
end
Upvotes: 0
Views: 99
Reputation: 18925
You can use implicit expansion implicitly (introduced in MATLAB R2016b) or explicitly by using MATLAB's bsxfun
to create that matrix:
% Parameters
EN = 10;
n = 6;
step = 3;
% Matrix (implict expansion, MATLAB >= R2016b)
etable = (0:step:EN*step-1).' + (1:n)
% Matrix (bsxfun, MATLAB < R2016b)
etable_legacy = bsxfun(@plus, (0:step:EN*step-1).', (1:n))
For the given parameter set, the outputs are:
etable =
1 2 3 4 5 6
4 5 6 7 8 9
7 8 9 10 11 12
10 11 12 13 14 15
13 14 15 16 17 18
16 17 18 19 20 21
19 20 21 22 23 24
22 23 24 25 26 27
25 26 27 28 29 30
28 29 30 31 32 33
etable_legacy =
1 2 3 4 5 6
4 5 6 7 8 9
7 8 9 10 11 12
10 11 12 13 14 15
13 14 15 16 17 18
16 17 18 19 20 21
19 20 21 22 23 24
22 23 24 25 26 27
25 26 27 28 29 30
28 29 30 31 32 33
You can change EN
(number of rows), the "number of columns" n
and/or the "step between rows" step
.
Hope that helps.
Upvotes: 4