CODEWITHSUNDEEP
pythonkeyword-argument
meag_a
meag_a

Reputation: 27

Disply all passed-in keyword arguments regardless what the key is

"Hi - Fairly rookie Python user and attempting some exercises in Python 3.1.. I was able to write a function taking LastName, Country as parameters and using **kwargs to display values passed in for state, salary, taxrate etc.

However, as a follow up I am trying to display keyword arguments regardless of the key - which is where I am getting stuck.

Looking for just the keyword arguments to be displayed rather than the passed in values

def myfunction(LastName, Country,**kwargs):
    print('Name:',LastName)
    print(Country)
    result = ""
    for arg in kwargs:
        result = arg
    return result
def main():
    myfunction('Smith','USA',state="NV",salary="55k",taxrate='2.00')
if __name__ == '__main__':
    main()

I am looking for an output like this:

Smith
USA
State   
Salary
Taxrate

Upvotes: 0

Views: 67

Answers (2)

Coronon
Coronon

Reputation: 387

If I interpret your question right, you may try this code:

# Returns a list in your desired format
def func(lastName, country, **kwargs):
    ret = [lastName, country]
    for key in kwargs:
        ret.append(key.capitalize())

    return ret

# Print
for i in func("", "", ...):
    print(i)

It basically creates a base list to which it then appends the kwargs keys. As you can see, kwargs is a dict and can be used as one

Reminder: You should upgrade to the newest version of Python (3.8.1) which can be download here

Upvotes: 0

Green Cloak Guy
Green Cloak Guy

Reputation: 24691

For all intents and purposes, kwargs is a dict. You can treat it as such:

def myfunction(last_name, country, **kwargs):
    print('name =', last_name)
    print('country =', country)
    for key, value in kwargs.items():
        print(key, '=', value)

>>> myfunction('Smith', 'USA', state="NV", salary="55k", taxrate='2.00')
name = Smith
country = USA
state = NV
salary = 55k
taxrate = 2.00

Upvotes: 1

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