Reputation: 25252
The following statements (in a loop) end in an error when row 1 is empty.
I would have expected the error to be silently ignored and the next sheet to be processed.
How come the code stops when the on error
is active ? I would expect it to ignore the error and continue processing after the skip
label.
Sub listSheets()
Dim sh As Worksheet, ar
Dim a
Set a = Application
For Each sh In ThisWorkbook.Sheets
Sheet1.Cells(3 + sh.Index, 1) = sh.Name
On Error GoTo skip
ar = sh.Range("1:1").SpecialCells(xlCellTypeConstants) 'code stops here if row 1 empty
ar = a.Transpose(a.Transpose(ar))
Sheet1.Cells(3 + sh.Index, 2) = Join(ar, "//")
ar = Null
skip:
Next sh
End Sub
Note: Error trapping is set to "Break on unhandled errors"
Upvotes: 1
Views: 1000
Reputation: 8104
A Resume statement is needed after an error occurs in which an error handler is enabled by the On Error statement. As per VBA reference...
If an error occurs while an error handler is active (between the occurrence of the error and a Resume, Exit Sub, Exit Function, or Exit Property statement), the current procedure's error handler can't handle the error.
For additional information have a look at the following link...
Upvotes: 1
Reputation: 75840
I believe the reason lays in the fact you allready encountered an error. You however never cleared your error from the handler. A second error won't skip over that line again.
So to replicate this I had three worksheets, a blank row in the second and third. Your On Error Goto
went through the second sheet but would return Error 1004
on the third.
You might want to include an Err.Clear
On Error Resume Next
ar = sh.Range("1:1").SpecialCells(xlCellTypeConstants) 'error 1004 on certain sheets
skip:
Err.Clear
Next sh
EDIT: Just found an alternative solution here
And even then, maybe even drop the error handling completely and use something like:
If WorksheetFunction.CountA(sh.Rows(1)) > 0 Then
ar = sh.Range("1:1").SpecialCells(xlCellTypeConstants)
End If
Upvotes: 3