Reputation: 563
hi to all regex master out there, I know you have a work around with regards to my problem. hehe
02-May-2011
or
22-May-2011
or
2-May-2011
(dd-MMM-yyyy) with yyyy not accepting any other characters than digit
Upvotes: 3
Views: 19314
Reputation: 1
Since it is date, which you are trying to find a match, using SimpleDateFormat instead of a regex based match check should be the appropriate solution. Hopefully, the below snippet should do the job.
public static boolean dateFormatValidate(String strDate,String dateFormat)
{
SimpleDateFormat formatter = new SimpleDateFormat(dateFormat);
String strParsed = null;
Date parsed =null;
try
{
parsed = formatter.parse(strDate);
strParsed = formatter.format(parsed);
}
catch (ParseException e)
{
MYLogger.logger.info(e.getMessage());
}
return strDate.equals(strParsed);
}
Upvotes: 0
Reputation: 1954
Okay, here are almost all possible regex variations of the Date pattern:
private final static Pattern DATE_PATTERN_1 =
Pattern.compile (
"(?:Sun|Mon|Tue|Wed|Thu|Fri|Sat) " +
"(?:Jan|Feb|Mar|Apr|May|June?|July?|Aug|Sept?|Oct|Nov|Dec) " +
"\\d\\d \\d\\d:\\d\\d:\\d\\d \\S+ \\d\\d\\d\\d", Pattern.CASE_INSENSITIVE);
private final static Pattern DATE_PATTERN_2 =
Pattern.compile (
"\\d{4}.\\d{2}.\\d{2}", Pattern.CASE_INSENSITIVE);
private final static Pattern DATE_PATTERN_3 =
Pattern.compile (
"\\d{2}.\\d{2}.\\d{4}", Pattern.CASE_INSENSITIVE);
private final static Pattern DATE_PATTERN_4 =
Pattern.compile (
"([0-9]{4})([0-9]{2})([0-9]{2})", Pattern.CASE_INSENSITIVE);
private final static Pattern DATE_PATTERN_5 =
Pattern.compile (
"^([12]\\d|3[01]).(Jan(uary)?|Feb(ruary)?|Mar(ch)?|Apr(il)?|May|June?|July?|Aug(ust)?|Sep(t(ember)?)?|Oct(ober)?|Nov(ember)?|Dec(ember)?).\\d{4})$", Pattern.CASE_INSENSITIVE);
Please note that "." character stand for any char.
Upvotes: 0
Reputation: 8341
/**
* Created with IntelliJ IDEA.
* User: S34N
* Date: 2013/07/30
* Time: 8:21 AM
* To change this template use File | Settings | File Templates.
*/
//Import the required classes/packages
import javax.swing.*;
import java.text.DateFormat;
import java.text.SimpleDateFormat;
import java.util.Date;
public class dateInputScan {
public static void main(String args[]) {
dateInputScan run = new dateInputScan();
run.dateInputScan();
}
public void dateInputScan() {
//Instantiating variables
String lvarStrDateOfTransaction = null;
DateFormat formatter = null;
Date lvarObjDateOfTransaction = null;
//Use one of the following date formats.
lvarStrDateOfTransaction = "29/07/2013";
//lvarStrDateOfTransaction = "29-07-2013";
//lvarStrDateOfTransaction = "20130729";
//lvarStrDateOfTransaction = "2013-07-29";
//lvarStrDateOfTransaction = "29/07/2013";
//You can also add your own regex (Regular Expression)
if (lvarStrDateOfTransaction.matches("([0-9]{2})/([0-9]{2})/([0-9]{4})")) {
formatter = new SimpleDateFormat("dd/MM/yyyy");
} else if (lvarStrDateOfTransaction.matches("([0-9]{2})-([0-9]{2})-([0-9]{4})")) {
formatter = new SimpleDateFormat("dd-MM-yyyy");
} else if (lvarStrDateOfTransaction.matches("([0-9]{4})([0-9]{2})([0-9]{2})")) {
formatter = new SimpleDateFormat("yyyyMMdd");
} else if (lvarStrDateOfTransaction.matches("([0-9]{4})-([0-9]{2})-([0-9]{2})")) {
formatter = new SimpleDateFormat("yyyy-MM-dd");
} else if (lvarStrDateOfTransaction.matches("([0-9]{4})/([0-9]{2})/([0-9]{2})")) {
formatter = new SimpleDateFormat("yyyy/MM/dd");
}
try {
lvarObjDateOfTransaction = formatter.parse(lvarStrDateOfTransaction);
JOptionPane.showMessageDialog(null, "Date: " + lvarObjDateOfTransaction);
} catch (Exception ex) { //Catch the Exception in case the format is not found.
JOptionPane.showMessageDialog(null, ex);
}
}
}
Upvotes: 0
Reputation: 14906
[0-9]{1,2}/[a-zA-Z]{3}/[0-9]{4}
That's assuming that the month is a 3-letter version: eg, Jan, Feb, Mar.
Updated version to match the changes to the question:
[0-9]{1,2}-[a-zA-Z]{3}-[0-9]{4}
As has been mentioned, this won't actually validate the date, it'll just validate that the string matches the format of: 1 or 2 numbers, a dash, 3 letters, a dash, 4 numbers.
Upvotes: 6
Reputation: 18747
Use SimpleDateFormat instead of using regexp. Read the tutorial at http://download.oracle.com/javase/tutorial/i18n/format/simpleDateFormat.html for more info.
Upvotes: 0
Reputation: 224905
^\d{1,2}/[a-zA-Z]+/\d{4}$
Is probably what you're looking for. Although the technically correct one is:
/^([12]\d|3[01])/(Jan(uary)?|Feb(ruary)?|Mar(ch)?|Apr(il)?|May|June?|July?|Aug(ust)?|Sep(t(ember)?)?|Oct(ober)?|Nov(ember)?|Dec(ember)?)/\d{4}$/i
Sorry for not validating February and the number of days in a month, but there are some things just not worth doing in regular expressions ;)
Upvotes: 4