CODEWITHSUNDEEP
pythonstringlistfindsubstring
Pedro Henrique
Pedro Henrique

Reputation: 300

Find a list of substring into a list of strings with python

I have a list of links and want to select some them based on list of subtrings into the link. I'd like to select the links with the substrings medalha or mencao-honrosa. Following a sample of selected links.

https://onciencias.org/resultado/detalhe/9-ano-ensino-fundamental/medalha-ouro
https://onciencias.org/resultado/detalhe/9-ano-ensino-fundamental/medalha-prata
https://onciencias.org/resultado/detalhe/9-ano-ensino-fundamental/medalha-bronze
https://onciencias.org/resultado/detalhe/9-ano-ensino-fundamental/mencao-honrosa
https://onciencias.org/resultado/detalhe/1-serie/medalha-ouro
https://onciencias.org/resultado/detalhe/1-serie/medalha-prata
https://onciencias.org/resultado/detalhe/1-serie/medalha-bronze
https://onciencias.org/resultado/detalhe/1-serie/mencao-honrosa
https://onciencias.org/resultado/detalhe/2-serie/medalha-ouro
https://onciencias.org/resultado/detalhe/2-serie/medalha-prata
https://onciencias.org/resultado/detalhe/2-serie/medalha-bronze
https://onciencias.org/resultado/detalhe/2-serie/mencao-honrosa
https://onciencias.org/resultado/detalhe/3-serie/medalha-ouro
https://onciencias.org/resultado/detalhe/3-serie/medalha-prata
https://onciencias.org/resultado/detalhe/3-serie/medalha-bronze
https://onciencias.org/resultado/detalhe/3-serie/mencao-honrosa
https://onciencias.org/resultado/detalhe/4-ano-tecnico/medalha-ouro
https://onciencias.org/resultado/detalhe/4-ano-tecnico/medalha-prata
https://onciencias.org/resultado/detalhe/4-ano-tecnico/medalha-bronze
https://onciencias.org/resultado/detalhe/4-ano-tecnico/mencao-honrosa

I did the following code and it's working. What's best another way to write this code and avoid to use or to separate the substrings.

for temp_link in list_links:
    if(str(temp_link).find('medalha') != -1 or str(temp_link).find('mencao-honrosa') != -1):
        links.append(url_home+temp_link[1:])
        print(url_home+temp_link[1:])

Thank you.

Upvotes: 0

Views: 59

Answers (1)

cmxu
cmxu

Reputation: 972

Try this,

[url for url in urls if 'medalha' in url or 'mencao-honrosa' in url]

or if you have a list of search terms, maybe something like this.

search_terms = ['medalha', 'mencao-honrosa']
[url for url in urls if any([term in url for term in search_terms])]

Upvotes: 3

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