Reputation: 29
Below is the class and in this, I'm using a Comparable interface. How can it is initialized with new
, though it is an interface?
public class PriorityQueueImpl {
@SuppressWarnings("rawtypes")
private Comparable[] pQueue;
private int index;
public PriorityQueueImpl(int capacity){
pQueue = new Comparable[capacity];
}
public void insert(Comparable item ){
if(index == pQueue.length){
System.out.println("The priority queue is full!! can not insert.");
return;
}
pQueue[index] = item;
index++;
System.out.println("Adding element: "+item);
}
@SuppressWarnings("unchecked")
public Comparable remove(){
if(index == 0){
System.out.println("The priority queue is empty!! can not remove.");
return null;
}
int maxIndex = 0;
// find the index of the item with the highest priority
for (int i=1; i<index; i++) {
if (pQueue[i].compareTo (pQueue[maxIndex]) > 0) {
maxIndex = i;
}
}
Comparable result = pQueue[maxIndex];
System.out.println("removing: "+result);
// move the last item into the empty slot
index--;
pQueue[maxIndex] = pQueue[index];
return result;
}
public static void main(String a[]){
PriorityQueueImpl pqi = new PriorityQueueImpl(5);
pqi.insert(34);
pqi.insert(23);
pqi.remove();
pqi.remove();
}
}
in the above code, Comparable Array initializes with the new operator. how is this possible?
Upvotes: 0
Views: 67
Reputation: 5393
new Comparable[capacity]
is not an initialisation ofComparable
interface but an array that can hold objects of type Comparable
. You can refer following section of JLS
Upvotes: 3