Reputation:
I have a simple question.
I have list, or a tuple, and I want to split it into many lists (or tuples) that contain the same elements.
I'll try to be more clear using an example:
(1,1,2,2,3,3,4) --> (1,1),(2,2),(3,3),(4,)
(1,2,3,3,3,3) --> (1,),(2,),(3,3,3,3)
[2,2,3,3,2,3] --> [2,2],[3,3],[2],[3]
How can I do? I know that tuples and lists do not have the attribute "split" so i thought that i could turn them into strings before. This is what i tried:
def splitt(l)
x=str(l)
for i in range (len(x)-1):
if x[i]!=x[i+1]:
x.split()
return x
Upvotes: 0
Views: 81
Reputation: 382
Try this
from itertools import groupby
input_list = [1, 1, 2, 4, 6, 6, 7]
output = [list(g) for k, g in groupby(input_list)]
Upvotes: 1
Reputation: 707
You also may try with for-loop:
def group_lt(list_or_tuple):
result = []
for x in list_or_tuple:
if not result or result[-1][0] != x:
result.append(type(list_or_tuple)([x]))
else:
result[-1] += type(list_or_tuple)([x])
return result
t = (1,1,2,2,3,3,4)
print(group_lt(t)) # [(1,1),(2,2),(3,3),(4,)]
l = [2,2,3,3,2,3]
print(group_lt(l)) # [[2,2],[3,3],[2],[3]]
Upvotes: 1
Reputation: 11929
You can use groupby.
import itertools as it
[list(grp) if isinstance(t,list) else tuple(grp) for k, grp in it.groupby(t)]
Examples:
>>> t = (1,2,3,3,3,3)
[(1,), (2,), (3, 3, 3, 3)]
>>> t = [2,2,3,3,2,3]
[[2, 2], [3, 3], [2], [3]]
Upvotes: 1