CODEWITHSUNDEEP
phpdate
user12067856
user12067856

Reputation:

PHP | Calculate remaining days but taking leap years into account

small problem to calculate the remaining days of the month starting today just I write:

$today = date('Y/m/d');

$timestamp = strtotime($today);

$daysRemaining = (int)date('t', $timestamp) - (int)date('j', $timestamp);

echo $daysRemaining;

and I get the remaining days

to do a test I entered a static date for the month of February

$timestamp = strtotime('2020-02-01');

$daysRemaining = (int)date('t', $timestamp) - (int)date('j', $timestamp);

echo $daysRemaining;

the question is here how do I calculate the remaining days in the month taking into account leap years, for example in February 2020 it will have 29 days and in this way I get out of it that remain 28

Upvotes: 2

Views: 323

Answers (1)

delboy1978uk
delboy1978uk

Reputation: 12374

Stop using the functions and start using the DateTime class!!! This code should explain itself.

<?php

$x = new DateTime('2020-02-17');         // create your date
$y = clone $x;                           // copy the date
$y->modify('last day of this month');    // alter the copy to the last day

echo $x->format('d') . "\n";             // show the day of the first date
echo $y->format('d') . "\n";             // show the day of the second date
echo $y->format('d') - $x->format('d');  // show the difference between the two

Output:

17 
29 
12

Check it here https://3v4l.org/8ZhOb

Check the DateTime class docs here https://www.php.net/manual/en/class.datetime.php

Upvotes: 3

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