Reputation: 1869
I have a table with the following data that I generated with a date table
date day_num (DAY_NUM % 7)
2019-07-09 0 0
2019-07-10 1 1
2019-07-11 2 2
2019-07-12 3 3
2019-07-13 4 4
2019-07-14 5 5
2019-07-15 6 6
2019-07-16 7 0
I basically want to get a week number that restarts at 0 and I need help figuring out the last part
The final output would look like this
date day_num (DAY_NUM % 7) week num
2019-07-09 0 0 1
2019-07-10 1 1 1
2019-07-11 2 2 1
2019-07-12 3 3 1
2019-07-13 4 4 1
2019-07-14 5 5 1
2019-07-15 6 6 1
2019-07-16 7 0 2
This is the sql I have so far
select
SUB.*,
DAY_NUM%7
FROM(
SELECT
DISTINCT
id_date,
row_number() over(order by id_date) -1 as day_num
FROM schema.date_tbl
WHERE Id_date BETWEEN "2019-07-09" AND date_add("2019-07-09",146)
Upvotes: 0
Views: 34
Reputation: 1269823
Building on your query:
select SUB.*, DAY_NUM%7,
DENSE_RANK() OVER (ORDER BY FLOOR(DAY_NUM / 7)) as weeknum
FROM (SELECT DISTINCT id_date,
row_number() over(order by id_date) -1 as day_num
FROM schema.date_tbl
WHERE Id_date BETWEEN "2019-07-09" AND date_add("2019-07-09", 146)
) x
Upvotes: 1