Reputation: 320
I have data set in following format:
STATION CODE DATE HOUR hr_rain
SHIVAMOGGA 163 06/09/18 00 1.0
SHIVAMOGGA 163 06/09/18 04 1.0
SHIVAMOGGA 163 06/09/18 05 NA
SHIVAMOGGA 163 06/09/18 06 1.5
SHIVAMOGGA 163 06/09/18 07 2.5
SHIVAMOGGA 163 06/09/18 08 NA
SHIVAMOGGA 163 06/09/18 09 0.0
SHIVAMOGGA 163 06/09/18 10 0.5
SHIVAMOGGA 163 06/09/18 11 0.5
SHIVAMOGGA 163 06/09/18 12 NA
SHIVAMOGGA 163 06/09/18 13 NA
SHIVAMOGGA 163 06/09/18 14 0.5
SHIVAMOGGA 163 06/09/18 15 0.5
SHIVAMOGGA 163 06/09/18 16 0.5
SHIVAMOGGA 163 06/09/18 17 0.5
SHIVAMOGGA 163 06/09/18 18 0.5
SHIVAMOGGA 163 06/09/18 19 0.5
SHIVAMOGGA 163 06/10/19 03 0.5
SHIVAMOGGA 163 06/10/19 05 NA
SHIVAMOGGA 163 06/10/19 06 NA
SHIVAMOGGA 163 06/10/19 07 NA
SHIVAMOGGA 163 06/10/19 08 0.5
SHIVAMOGGA 163 06/10/19 09 0.0
SHIVAMOGGA 163 06/10/19 10 0.0
Here the parameter rainfall is in hourly accumulated format. I'm interested into hourly rainfall rate. The measurement starts everyday at 09 HOUR & sometimes observations are missing, so I tried to fill NA values (3 or more consecutive NA's will be left unchanged and consecutive NA's less than 2 in number are replaced & NA's at 8 HOUR has given the previous value) by grouping for 09 HOUR.
df1 <- df %>%
group_by(STATION, CODE, gr = cumsum(HOUR == '09')) %>%
mutate(hr_rain = na.approx(hr_Rain, rule = 2, maxgap = 2, na.rm = FALSE))
Again to calculate hourly rainfall rate I tried to group df1
with:
hourly_df <- df1 %>%
group_by(STATION, CODE , grp = cumsum(HOUR == '09')) %>%
mutate(RAINFALL = hr_rain - lag(hr_rain, default = 0))
But it's not working. It creates first group and then second group continues till end of dataframe. The result is coming like:
STATION CODE DATE HOUR hr_rain NUM_NA gp grp RAINFALL
SHIVAMOGGA 163 06/09/18 00 1.0 2 0 0 1
SHIVAMOGGA 163 06/09/18 04 1.0 2 0 0 0
SHIVAMOGGA 163 06/09/18 05 1.25 1 0 0 0.25
SHIVAMOGGA 163 06/09/18 06 1.5 1 0 0 0.25
SHIVAMOGGA 163 06/09/18 07 2.5 1 0 0 1
SHIVAMOGGA 163 06/09/18 08 2.5 1 0 0 0
SHIVAMOGGA 163 06/09/18 09 0.0 1 1 1 -2.5
SHIVAMOGGA 163 06/09/18 10 0.5 2 1 1 0.5
SHIVAMOGGA 163 06/09/18 11 0.5 2 1 1 0
SHIVAMOGGA 163 06/09/18 12 0.5 2 1 1 0
SHIVAMOGGA 163 06/09/18 13 0.5 2 1 1 0
SHIVAMOGGA 163 06/09/18 14 0.5 7 1 1 0
SHIVAMOGGA 163 06/09/18 15 0.5 7 1 1 0
SHIVAMOGGA 163 06/09/18 16 0.5 7 1 1 0
SHIVAMOGGA 163 06/09/18 17 0.5 7 1 1 0
SHIVAMOGGA 163 06/09/18 18 0.5 7 1 1 0
SHIVAMOGGA 163 06/09/18 19 0.5 7 1 1 0
SHIVAMOGGA 163 06/10/19 03 0.5 7 1 1 0
SHIVAMOGGA 163 06/10/19 05 NA 3 1 1 NA
SHIVAMOGGA 163 06/10/19 06 NA 3 1 1 NA
SHIVAMOGGA 163 06/10/19 07 NA 3 1 1 NA
SHIVAMOGGA 163 06/10/19 08 0.5 1 1 1 0.5
SHIVAMOGGA 163 06/10/19 09 0.0 2 2 1 -0.5
SHIVAMOGGA 163 06/10/19 10 0.0 2 2 1 0
With this for 9 HOUR I'm getting negative values, which I want to start with value of hr_rain (that's why I was trying to create another grouping by 09 HOUR) for that field. Thanks in advance for any help!
Upvotes: 0
Views: 91
Reputation: 388797
Since both the groups are same no need to calculate them differently, you can combine them and calculate hr_rain
and RAINFALL
together.
library(dplyr)
df %>%
group_by(STATION, CODE, gr = cumsum(HOUR == '09')) %>%
mutate(hr_rain = zoo::na.approx(hr_rain, rule = 2, maxgap = 2, na.rm = FALSE),
RAINFALL = hr_rain - lag(hr_rain, default = 0))
data
df <- structure(list(STATION = c("SHIVAMOGGA", "SHIVAMOGGA", "SHIVAMOGGA",
"SHIVAMOGGA", "SHIVAMOGGA", "SHIVAMOGGA", "SHIVAMOGGA", "SHIVAMOGGA",
"SHIVAMOGGA", "SHIVAMOGGA", "SHIVAMOGGA", "SHIVAMOGGA", "SHIVAMOGGA",
"SHIVAMOGGA", "SHIVAMOGGA", "SHIVAMOGGA", "SHIVAMOGGA", "SHIVAMOGGA",
"SHIVAMOGGA", "SHIVAMOGGA", "SHIVAMOGGA", "SHIVAMOGGA", "SHIVAMOGGA",
"SHIVAMOGGA"), CODE = c(163, 163, 163, 163, 163, 163, 163, 163,
163, 163, 163, 163, 163, 163, 163, 163, 163, 163, 163, 163, 163,
163, 163, 163), DATE = c("06/09/18", "06/09/18", "06/09/18",
"06/09/18", "06/09/18", "06/09/18", "06/09/18", "06/09/18", "06/09/18",
"06/09/18", "06/09/18", "06/09/18", "06/09/18", "06/09/18", "06/09/18",
"06/09/18", "06/09/18", "06/10/19", "06/10/19", "06/10/19", "06/10/19",
"06/10/19", "06/10/19", "06/10/19"), HOUR = c("00", "04", "05",
"06", "07", "08", "09", "10", "11", "12", "13", "14", "15", "16",
"17", "18", "19", "03", "05", "06", "07", "08", "09", "10"),
hr_rain = c(1, 1, NA, 1.5, 2.5, NA, 0, 0.5, 0.5, NA, NA,
0.5, 0.5, 0.5, 0.5, 0.5, 0.5, 0.5, NA, NA, NA, 0.5, 0, 0)), row.names = c(NA,
-24L), class = "data.frame")
Upvotes: 1