CODEWITHSUNDEEP
javascript
verojoucla
verojoucla

Reputation: 649

How compare numbers in javascript

I have two numbers that contain every one from 1 to 6 digits. I would like to compare them using JavaScript and to put a percentage according their matching.

The comparison should be done from left to right.

Example: 

if 6D matching then 100%  ==> Example: (value_1: 987456, value_2: 987456) 
if 5D matching then 90%   ==> Example: (value_1: 987450, value_2: 987456)
if 4D matching then 80%   ==> Example: (value_1: 987400, value_2: 987456)
if 3D matching then 60%   ==> Example: (value_1: 987000, value_2: 987456)
if 2D matching then 40%   ==> Example: (value_1: 980000, value_2: 987456)
else  0%           ==> Example: (value_1: 010101, value_2: 987456)

I hope that I was clear. Can you suggest me a solution how can I do it in a function ? Thank you

Upvotes: 1

Views: 4357

Answers (4)

sourav satyam
sourav satyam

Reputation: 986

  • Convert number to string (string1, string2)

  • split one of the string greater length (string1 > string2) ? string1.split('')

  • loop every element of string2

  • initialize a counter to 0

  • check if element of string2 exists in string1 if (string1.indexOf(string2[i]) > -1) {count += 1}

  • finally for percentage (count/string1.length) * 100

` 

var a = String(839123)
var b = String(829156)
var count = 0;
for (let i = 0 ; i < b.length; i++) {
    if (a.indexOf(b[i]) > -1) {
        count += 1;
    }
}
alert(count); //Match Count`

Upvotes: 1

Burak Ayyildiz
Burak Ayyildiz

Reputation: 465

Firstly transform the number to a string and iterate over them. for example:

let number1 = 12345 + ""
let number2 = 12346 + ""
let percentageMaps = ["0%", "0%", "40%", "60%", "80%", "90%", "100%"]

function getPercentage(number1, number2) {
  counter = 0;
  for (var i = 0; i < number1.length; i++) {

    if (number1.charAt(i) == number2.charAt(i)) {
      counter++;
    }

  }
  return percentageMaps[counter]
}

console.log(getPercentage(number1, number2))

Upvotes: 3

arizafar
arizafar

Reputation: 3132

You can simply take the difference of numbers and if the difference is 0 then take empty string else the length/order of difference.

keep the percentages in an array on the index of the same order it should be.

let per = [100, 90, 80, 60, 40]
calcPer = (num1, num2) => per[(Math.abs(num1 - num2) || '').toString().length] || 0;

console.log(calcPer(987456, 987456))
console.log(calcPer(987456, 987450))
console.log(calcPer(987456, 987400))
console.log(calcPer(987456, 987000))
console.log(calcPer(987456, 900000))

Upvotes: 5

Guillem Bonet
Guillem Bonet

Reputation: 56

You should do something like: 

let value_1 = 123456
let value_2 = 123000

let percentage = 100
while (percentage > 0 && value_1 !== value_2) {
    value_1 = Math.floor(value_1/10)
    value_2 = Math.floor(value_2/10)
    if (percentage > 80) percentage -= 10
    else if (percentage > 40) percentage -= 20
    else percentage = 0
}
console.log(percentage)

Hope this helps

Upvotes: 1

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