CODEWITHSUNDEEP
pythonlistloopstkinterenumerate
Daniel
Daniel

Reputation: 23

Tkinter in Python, enumerate

I need your help. I want to make a few labels. After clicked, the number on every label should change to a text accordiong to the number. I tried this, but it just changes the text on every label to the last item in the list2. What should I do to make it change accordingly? Numbers and texts are on the same position in both lists.

import tkinter as tk

root = tk.Tk()

list1 = [["one", "two", "three", "four"], ["five", "six", "seven", "eight"],["nine","ten","eleven","twelve"]]
list2 = [["1","2","3","4"], ["5", "6", "7", "8"],["9", "10", "11", "12"]]

def change_label(event):
    for row, rowinlist in enumerate(list2):
        for column, text2 in enumerate(rowinlist):    
            event.widget.configure(text=text2)

for row, rowinlist in enumerate(list1):
    for column, text in enumerate(rowinlist):
        label = tk.Label(text=text, width=15, bd=1, relief="raised")
        label.grid(row=row, column=column)
        label.bind("<1>", change_label)
        x = text

root.mainloop()

Upvotes: 0

Views: 776

Answers (1)

acw1668
acw1668

Reputation: 46678

It is because you go through all the items in list2 and set the text of event.widget to it, so the final result is the last item of list2.

You need to save the row and column of each label and use them to set its text:

def change_label(event):
    row, col = event.widget.pos # get the position of clicked label
    event.widget.configure(text=list2[row][col])

for row, rowinlist in enumerate(list1):
    for column, text in enumerate(rowinlist):
        label = tk.Label(text=text, width=15, bd=1, relief="raised")
        label.grid(row=row, column=column)
        label.bind("<1>", change_label)
        label.pos = (row, column) # save the position of label

Upvotes: 1

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