CODEWITHSUNDEEP
python-3.xlistfor-loopif-statement
miyashiro
miyashiro

Reputation: 25

Don't know how to use "if in" in a list

i'm doing "the feeling lucky project" from "automate the boring stuff with python" which i have to open 5 new tabs in the browser based on what you search on google. Using bs4 i managed to get all the links related with search on a list named "links" which looked like this:

list

and i noticed that before the '#' is the link i actually need, so i tried

for i in links:
if '#' in i:
    print(links.index(i))

and i would get index of '#' - 1, so i could get the link. But when i run the code it just prints 1, 1, 1, 1, 1, 1, 1. Which is the index of the first '#' and my loop is stuck there. Can someone explain me why?

Thank you!

Upvotes: 0

Views: 39

Answers (1)

OneCricketeer
OneCricketeer

Reputation: 191743

Which is the index of the first '#'

It should be the index of the first 'i' based on your (original} code

This is checking if the link string contains # as a character, which indirectly ensures its in the list, I guess... But likely not what you want 

for i in links:
   if '#' in i:

If you just want one result, remove the loop and use the correct character 

idx = links.index('#')
if idx >= 0:
    print(idx, links[idx])
else:
    print('not found')

'#' in links just returns true or false, it won't tell you where it is

If you want all matches, that would be this (though just a list of #, which seems pointless) 

[x for x in links if x == '#']

If you want all links before #, you can get the links directly, or you can append in the index as well 

res = [] 
for i in range(1,len(links)):  # start one ahead because we're subtracting later 
    if links[i] == '#':
        res.append(links[i-1])
print(res)

Upvotes: 1

Related Questions