CODEWITHSUNDEEP
python
disney82231
disney82231

Reputation: 199

How does only not appear Year when I use datetime.strptime?

I have a str 'Jan 22 16:47:37',I want to convert it to time type.

datetime.strptime('Jan 22 16:47:37', "%b %d %H:%M:%S")

I get

datetime.datetime(1900, 1, 22, 16, 47, 37)

I hope the result of the code is datetime.datetime( 1, 22, 16, 47, 37)

How can I do?

Thanks

Upvotes: 0

Views: 44

Answers (1)

Sameeresque
Sameeresque

Reputation: 2602

You could do this:

value=datetime.strptime('Jan 22 16:47:37', "%b %d %H:%M:%S")

(value.month,value.day,value.hour,value.minute,value.second)

You can't get a datetime object without the year. Refer to the definition of datetime object 

?datetime

Docstring:
datetime(year, month, day[, hour[, minute[, second[, microsecond[,tzinfo]]]]])

The year, month and day arguments are required. tzinfo may be None, or an
instance of a tzinfo subclass. The remaining arguments may be ints or longs.
Type:      type

Upvotes: 1

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