CODEWITHSUNDEEP
cssscrapyhref
mikezang
mikezang

Reputation: 2499

How to extract text in similar a href by scrapy

I want to extract text as below,

SUBTHEME_SELECTOR = '.subtheme::text',
YEAR_SELECTOR = '.year::text'
but I am not sure how to extract Theme, can you help me?
THEME_SELECTOR = '//a[contains(@href, "/sets/theme-")]/@href' ???

<div class='tags floatleft'>
    <a href='/sets/10251-1/Brick-Bank'>10251-1</a> 
    <a href='/sets/theme-Creator-Expert'>Creator Expert</a> 
    <a class='subtheme' href='/sets/theme-Creator-Expert/subtheme-Modular-Buildings'>Modular Buildings</a> 
    <a class='year' href='/sets/theme-Creator-Expert/year-2016'>2016</a> 
</div>

Upvotes: 0

Views: 31

Answers (1)

Tom&#225;š Linhart
Tom&#225;š Linhart

Reputation: 10220

You got it right. You can test it quite simply even without actually scraping the site:

import scrapy

TEXT = """
<div class='tags floatleft'>
    <a href='/sets/10251-1/Brick-Bank'>10251-1</a> 
    <a href='/sets/theme-Creator-Expert'>Creator Expert</a> 
    <a class='subtheme' href='/sets/theme-Creator-Expert/subtheme-Modular-Buildings'>Modular Buildings</a> 
    <a class='year' href='/sets/theme-Creator-Expert/year-2016'>2016</a> 
</div>
"""

s = scrapy.Selector(text=TEXT)
link = s.xpath('//a[contains(@href,"/sets/theme-")]/@href').extract_first()
text = s.xpath('//a[contains(@href,"/sets/theme-")]/text()').extract_first()
print(link)
print(text)

Produces:

/sets/theme-Creator-Expert
Creator Expert

Upvotes: 1

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