CODEWITHSUNDEEP
javaapache-sparkjava-pair-rdd
bib
bib

Reputation: 1040

how to apply flatMapToPair on a given rdd?

I have a JavaPairRDD<String, List<Tuple2<Integer, Integer>>> named rddA. For example (after collecting rddA): [(word1,[(187,267), (224,311), (187,110)]), (word2,[(187,200), (10,90)])]. Thus, for example, word1 is the key and value is [(187,267), (224,311), (187,110)])].

How can I define the corresponding JavaPairRDD<Integer, List<Integer>> to get the following ouptput:

[(187, [267, 110, 200]), (224,[311]), (10,[90])]

So, the obtained JavaPairRDDincludes three keys: 187, 224 and 10. And for example, the key 187 has [267, 110, 200] as a list value.

Upvotes: -3

Views: 1965

Answers (1)

Oli
Oli

Reputation: 10406

You simply need to flatten the list of tuples (second value of your tuple) and group by the first element of the tuple.

JavaPairRDD<Integer, List<Integer>> result = rddA
                .flatMapValues(x -> x) // flattening the list
                .mapToPair(x -> x._2) // getting rid of the first key
                .groupByKey()
                .mapValues(x -> { // turning the iterable into a list
                    List<Integer> list = new ArrayList<>();
                    x.forEach(list::add);
                    return list;
                });

Upvotes: 1

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