CODEWITHSUNDEEP
concurrencyrust
jeremie
jeremie

Reputation: 1131

Is there any way to convert a Rc<T> into an Arc<T>?

I have a graph node:

pub struct GraphNode<T>
where
    T: Clone,
{
    pub f: GraphLikeFunc<T>,
    pub m: String,
    pub children: Vec<Rc<GraphNode<T>>>,
    id: Uuid,
}

I'm trying to convert it to: 

pub struct ConcurrentGraphNode<T>
where
    T: Clone,
{
    pub f: GraphLikeFunc<T>,
    pub m: String,
    pub children: Vec<Arc<ConcurrentGraphNode<T>>>,
    id: Uuid,
}

Upvotes: 0

Views: 909

Answers (1)

Boiethios
Boiethios

Reputation: 42749

You cannot do such a thing without rebuilding the whole graph. The main difference between Rc and Arc is that Rc does not implement Send and Sync while Arc does.

Those guarantees are checked at compile-time, so there is no way to switch directly between those two at runtime: you have to consume your GraphNode to build a ConcurrentGraphNode from scratch.

Upvotes: 3

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