CODEWITHSUNDEEP
ccharvariable-assignmentlvalue
Mysterigs
Mysterigs

Reputation: 483

Expression must be a modifiable L-value

I have here char text[60];

Then I do in an if: 

if(number == 2)
  text = "awesome";
else
  text = "you fail";

and it always said expression must be a modifiable L-value.

Upvotes: 47

Views: 170285

Answers (1)

MByD
MByD

Reputation: 137312

lvalue means "left value" -- it should be assignable. You cannot change the value of text since it is an array, not a pointer.

Either declare it as char pointer (in this case it's better to declare it as const char*):

const char *text;
if(number == 2) 
    text = "awesome"; 
else 
    text = "you fail";

Or use strcpy:

char text[60];
if(number == 2) 
    strcpy(text, "awesome"); 
else 
    strcpy(text, "you fail");

Upvotes: 68

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