CODEWITHSUNDEEP
php
Pascal Driss
Pascal Driss

Reputation: 1

Php 7.3.13 Invalid argument supplied for foreach()

Since my host has updated php from version 7.0.3 to version 7.3.13 of php, I am getting the following error:

Invalid argument supplied for foreach()

It worked perfectly before the version change, if I use var_export on the function, with version 7.0.3 I get:

array (
    0 => 'block_menu.html',
    1 => 'block_fiches_pratiques.html',
    2 => 'block_fiche_aleatoire.html',
    3 => 'block_random_annonces.html',
    4 => 'block_consult.html',
    5 => 'block_random_oquerhtml',
    6 => 'block_user_information.html',
    7 => 'block_horoscope.html',
    8 => 'block_favoris.html',
    9 => 'block_links.html',)

If I use var_export on the function, with version 7.3.13, it shows me 10 times the first letter of the character string, not array (bbbbbbbbbbb)

Here is the offending code:

if($left_block_ary !='') {
    foreach ($left_block_ary as $block => $value){
    $template->assign_block_vars('left_block_files', array(
    'LEFT_BLOCKS'       => portal_block_template($value),
    'LEFT_BLOCK_ID'     => $left_block_id[$block],
    'LEFT_BLOCK_SOURCE' => htmlspecialchars_decode(smilies_pass(censor_text($left_block_source[$block]))),
    'LEFT_BLOCK_NOM'    => $left_block_nom[$block],                     
    ));
    } } else {}

Thank you for your help...

Upvotes: 0

Views: 462

Answers (3)

Pascal Driss
Pascal Driss

Reputation: 1

Thanks for your help.

But precisely the problem is there, with the php version before 7.3.13, with the test of the var_export function ($ left_block_ary); , it shows me the table well. Since version 7.3.13, it displays 10 times the first letter of the character chain, not array (bbbbbbbbbbb).

See my first post.

I changed if ($ left_block_ary! = '') To if (! Empty ($ left_block_ary)), it makes the code cleaner, but of course it doesn't change the error.

Upvotes: 0

Jonel Zape
Jonel Zape

Reputation: 42

The error message caused by $left_block_ary is not an array. If the variable $left_block_ary can not only be an array then you should put validation using is_array() to check if variable is an array before using foreach() and you may also use empty() to determine if has value like this example:

if (is_array($left_block_ary)) {

    foreach ($left_block_ary as $block => $value){
        echo $value."<br>";
    }

    if (empty($left_block_ary)) {
       echo 'array is empty'
    }
} else {
    echo 'not array';
}

Upvotes: 0

Johhn
Johhn

Reputation: 1049

Your if($left_block_ary !='') is what is not checking or isn't working correctly. $left_block_ary is an array and therefore it will never be equal to '' thus that check always passes even in cases where the array is empty instead you can use the 

if(!empty($left_block_ary)) {
   //perform your loop here
}

check to check whether the array is empty or not.

Upvotes: 1

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