CODEWITHSUNDEEP
javaservletsservlet-filters
Hans Sausage
Hans Sausage

Reputation: 55

ServletRequest get name of actual page

I am using a Filter and the doFilter-Function. I would like to know which site is being requested. Some function giving me something like /firstDirectoryInWebDirectory/lala.jsp would be perfect.

What is the way to go here? Using the context will be the right way, but I can't find any good method :-(

Thanks

Upvotes: 3

Views: 11679

Answers (2)

Alex Ureche
Alex Ureche

Reputation: 401

When I just started learning Java EE, it was casual to mix-up ServletRequest and HttpServletRequest methods. As Bozho said, type casting is necessary to access required methods.

This code will log access time and IP when the servlet named "Test" will be requested:

if (((HttpServletRequest)request).getServletPath().equals("/Test")){
            String IP = request.getRemoteAddr();
            System.out.println("Test Servlet:: Logged IP "+ IP + ", Time :" + new Date().toString());
        }
filterChain.doFilter(request,response);

Basically, the request object is casted from a generic request into HTTP Request and only then the return String of getServletPath() can be compared to whatever you want ("/Test" or "/firstDirectoryInWebDirectory/lala.jsp" or "whatever.html").

Upvotes: 0

Bozho
Bozho

Reputation: 597116

request.getRequestURI() should return the part of the URL after the domain.

From there, you can strip the request.getContextPath()

(You'd have to cast the ServletRequest to HttpServletRequest first)

Upvotes: 13

Related Questions