Reputation: 26212
I'm executing rather complex like this :
session.createSQLQuery("query").setResultTransformer(Transformers.aliasToBean(CheckIn.class));
I'm using couple of AS
(ex: select column as
columnName from my Table) in my query and hibernate always throws this exception :
Exception in thread "main" org.hibernate.PropertyNotFoundException: Could not find setter for inputrecords on class com.letmedical.store.CheckIn
at org.hibernate.property.ChainedPropertyAccessor.getSetter(ChainedPropertyAccessor.java:44)
at org.hibernate.transform.AliasToBeanResultTransformer.transformTuple(AliasToBeanResultTransformer.java:57)
at org.hibernate.hql.HolderInstantiator.instantiate(HolderInstantiator.java:69)
at org.hibernate.loader.custom.CustomLoader.getResultList(CustomLoader.java:330)
at org.hibernate.loader.Loader.listIgnoreQueryCache(Loader.java:2104)
at org.hibernate.loader.Loader.list(Loader.java:2099)
at org.hibernate.loader.custom.CustomLoader.list(CustomLoader.java:289)
at org.hibernate.impl.SessionImpl.listCustomQuery(SessionImpl.java:1695)
at org.hibernate.impl.AbstractSessionImpl.list(AbstractSessionImpl.java:142)
at org.hibernate.impl.SQLQueryImpl.list(SQLQueryImpl.java:152)
at com.letmedical.store.Test.main(Test.java:37)
But there are setters for each class field. What do I do? google doesn't help much since this is not strictly hibernate error.
Update :
I tried to iterate trough result list :
List<CheckIn> list = query.list();
for (CheckIn object : list) {
System.out.println(object.getAppTime());
}
I get this error :
Exception in thread "main" java.lang.ClassCastException: [Ljava.lang.Object; cannot be cast to com.letmedical.store.CheckIn
at com.letmedical.store.Test.main(Test.java:41)
But all attributes of my object are inside this object but I can't cast it to my object CheckIn. Anyone had this issue?
Update II :
Here is getter/setter :
private Integer inputRecords;
public Integer getInputRecords() {
return inputRecords;
}
public void setInputRecords(Integer inputRecords) {
this.inputRecords= inputRecords;
}
My Hibernate mapping :
<property name="inputRecords" type="java.lang.Integer">
<column name="inputRecords" not-null="false" />
</property>
table column is named inputrecords
is there a way arround?
Upvotes: 0
Views: 1429
Reputation: 120198
from your stacktrace, you have a field 'inputrecords'. This should be
inputRecords
and the setter should be
public void setInputRecords(...){
...
}
Upvotes: 1