CODEWITHSUNDEEP
sqlsql-servert-sqlsql-server-2008
user9167864
user9167864

Reputation: 21

SQL take just the numeric values from a column

I have the follow data in a column:

aud_344266_jayde_adams
int_343581_jtou_s5_ep1
of_344289_geordie_s21_rig_c
soft_343726_24hrpc_s4_norbiton
on_334195_sas_s5_1007_1008

and I only want to return the following:

344266
343581
344289
343726
334195

As you can tell there is a pattern in the number I want to return. They have to underscore before and after them and also have a length of 6 characters.

Is there any way of doing this in SQL Server?

Upvotes: 0

Views: 74

Answers (4)

Gordon Linoff
Gordon Linoff

Reputation: 1269633

For your example data, this works:

select left(stuff(t.col, 1, patindex('%[_][0-9][0-9][0-9][0-9][0-9][0-9][_]%', t.col), ''), 6)

Or even more simply:

select substring(t.col, patindex('%[_][0-9][0-9][0-9][0-9][0-9][0-9][_]%', t.col) + 1, 6)

Here is a db<>fiddle.

Upvotes: 3

Nguyễn Văn Phong
Nguyễn Văn Phong

Reputation: 14208

You can use SUBSTRING combine with CHARINDEX to achieve it

select substring(value, CHARINDEX('_', value) + 1, 6)
from TempTable

Demo on db<>fiddle

Output

344266
343581
344289
343726
334195

Upvotes: 1

Alan Burstein
Alan Burstein

Reputation: 7918

APPLY is your friend.

-- Sample Data
DECLARE @yourtable TABLE (SomeString VARCHAR(100));
INSERT @yourtable (SomeString) VALUES 
  ('aud_344266_jayde_adams'),('int_343581_jtou_s5_ep1'),('of_344289_geordie_s21_rig_c'),
    ('soft_343726_24hrpc_s4_norbiton'),('on_334195_sas_s5_1007_1008');

-- Solution
SELECT      TheNumber = SUBSTRING(t.SomeString,d1.Pos,d2.Pos-d1.Pos)
FROM        @yourtable AS t
CROSS APPLY (VALUES(CHARINDEX('_',t.SomeString)+1))      AS d1(Pos)
CROSS APPLY (VALUES(CHARINDEX('_',t.SomeString,d1.Pos))) AS d2(Pos);

Returns:

TheNumber
----------
344266
343581
344289
343726
334195

Upvotes: 1

zip
zip

Reputation: 4061

You can use left, right and charindex function

example:

declare @row as varchar(100) = 'aud_344266_jayde_adams'

select @row,  right(@row, len(@row)-charindex('_',@row)), left(right(@row, len(@row)-charindex('_',@row)),-1 + charindex('_',right(@row, len(@row)-charindex('_',@row))))

For your table you do:

select left(right(_Column, len(_Column)-charindex('_',_Column)),-1 + charindex('_',right(_Column, len(_Column)-charindex('_',_Column))))
From Tbl

Upvotes: 1

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