CODEWITHSUNDEEP
typescript
Sam
Sam

Reputation: 1249

typescript callback function return function

I have function take function as argument and return new function. Returned function called with options params and call styleCallback function. I dont know how to pass options type to styleCallback

const makeStyle = (styleCallback) => {
    return (options) =>{
        theme = getTheme();
        return styleCallback(theme, options)
    }
}

I tried with generics but it not worked

const makeStyle = (styleCallback: (theme: Theme, props: T) => any) => {
    return <T>(options: T) =>{
        theme = getTheme();
        return styleCallback(theme, options)
    }
}

Upvotes: 0

Views: 91

Answers (1)

Mat Sz
Mat Sz

Reputation: 2552

Placing the type variable in the main function should resolve your issue.

const makeStyle = <T>(styleCallback: (theme: Theme, props: T) => any) => {
    return (options: T) => {
        let theme = getTheme();
        return styleCallback(theme, options);
    }
}

Upvotes: 1

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