CODEWITHSUNDEEP
androidkotlin
Ragini
Ragini

Reputation: 775

Regex to split string in kotlin

I want to group strings based on character.

For eg. I want to split following url in two groups

group 1 -   /viewarticle/abd-fdj-gfg-to
group2 - 628882 (last string)

/viewarticle/abd-fdj-gfg-to-628882

I tried this " -(?!.*-) " but it is not working.

I have to use only regex not split function.

Any help would be appreciated.

Upvotes: 3

Views: 2167

Answers (2)

Tim Biegeleisen
Tim Biegeleisen

Reputation: 521279

You may try splitting using a lookbehind, e.g. split on:

(?<=-to)-

You could also make the lookbehind more specific:

(?<=abd-fdj-gfg-to)-

But this would only make sense if what precedes -to would always be the same.

Edit:

If you need to split on the last hyphen, then use the negative lookahead:

-(?!.*-)

Upvotes: 3

Pavneet_Singh
Pavneet_Singh

Reputation: 37404

You can simply use groups () with .*- to capture the first input and the rest as second so use:

(.*-)([a-zA-Z\\d]+)

Demo

val regex = "(.*-)([a-zA-Z\\d]+)".toRegex() // use only (\\d+) for digits
val matchResults = regex.find("/viewarticle/abd-fdj-gfg-to-628882")!!
val (link, id) = matchResults.destructured
println("Link: $link \nID: $id")

Details:

.*- : match anything till last -

[a-zA-Z\\d]+ : match 0 or more characters a-zA-Z or digits

Upvotes: 4

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