nobody
nobody

Reputation: 1949

Parsing a currency String in java

Suppose I'm supplied with a String which is like "$123,456,56.25" or "123'456.67" or something similar to this (with digits and a decimal point and some seperator like , or ' or something else which is not predictable). I need to write a method which takes an argument like the one above and returns a String like "12345656.25" or "123456.67" respectively.

Could you please suggest the most efficient and readable code to achieve this?

Note: I'm aware of going through each indexes and checking for whether its retunrs true for Character.isDigit(charAtInedx) or if(charAtInedx == '.') I'm looking for a more optimized solution both in terms of efficiency and readability

Thanks.

Upvotes: 10

Views: 26469

Answers (3)

Mosawer Mahboob
Mosawer Mahboob

Reputation: 1

To parse a currency instance in Java, you can use the NumberFormat.getCurrencyInstance object. For example:

import java.text.NumberFormat;
import java.text.ParseException;

public class Main {
    public static void main(String[] args) throws ParseException {
        NumberFormat currency = NumberFormat.getCurrencyInstance(); // get the currency formatter
        String price = currency.format(19292.282); // format as a currency
        System.out.println(price); // $19,292.28

        Number parsePrice = currency.parse(price);
        System.out.println(parsePrice); // 19292.28
    }
}

Keep in mind that this is just a quick example, and you would need to account for exceptions as well.

Upvotes: 0

Alan Escreet
Alan Escreet

Reputation: 3549

If you want to handle monetary values correctly, you will want to have a look at the NumberFormat class, specifically for your case NumberFormat.parse(String). The following article also discusses the problems (and solutions) to handling money in Java:

http://www.javapractices.com/topic/TopicAction.do?Id=13

Other related classes include: Currency and of course BigDecimal.

Upvotes: 8

Sean Patrick Floyd
Sean Patrick Floyd

Reputation: 298908

String newStr = oldStr.replaceAll("[^\\d.]+", "")

This will drop any character that is not either a digit or a period

Upvotes: 19

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