CODEWITHSUNDEEP
awkprintingcount
user12859525
user12859525

Reputation: 1

matching criteria and printing with awk

I have a file and I am trying to get this following information. There are a few headers and my condition is as follows that returns the count of time "PO" is found in column 5.However I want to print the entries that match the criteria as well. How do I do that?

awk 'BEGIN {count = 0} $5 == "PO" && $13 <0.01 {count++} END {print(count)}' 1.genome

Upvotes: 0

Views: 50

Answers (1)

Rusty Lemur
Rusty Lemur

Reputation: 1875

You can do multiple things inside the curly braces. If you keep it as a one-liner, separate each command by a semicolon. E.g.

awk 'BEGIN {count = 0} $5 == "PO" && $13 <0.01 {print $0; count++} END {print count}' 1.genome

As the complexity grows, you may want to format it on multiple lines:

awk '
    BEGIN {
        count = 0
    } 

    $5 == "PO" && $13 < 0.01 {
        print $0
        count++
    } 

    END {
        print count
    }
' 1.genome

Upvotes: 1

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