CODEWITHSUNDEEP
java
Priyanka Taneja
Priyanka Taneja

Reputation: 575

Split function returning whitespace character at the begining

I have a string String A = "/a/./b/../../c/" and I want to split based on /. I am writing this way

String[] strings = A.split("/");

AND I am getting this array data. Why I am getting empty space at [0]th position. I want data starting from s[1] position.

Value of s is ====:
Value of s is ====:a
Value of s is ====:.
Value of s is ====:b
Value of s is ====:..
Value of s is ====:..
Value of s is ====:c


Thanks in Advance

Upvotes: 1

Views: 50

Answers (3)

Arvind Kumar Avinash
Arvind Kumar Avinash

Reputation: 79085

@dave has already answered the why part of your question. Answering the following remaining part of your question:

I want data starting from s[1] position.

You can use Arrays.copyOfRange to get a copy of the array of the required range.

import java.util.Arrays;

public class Main {

    public static void main(String[] args) {
        String A = "/a/./b/../../c/";
        String[] strings = Arrays.copyOfRange(A.split("/"), 1, A.split("/").length);
        System.out.println(Arrays.toString(strings));
    }
}

Output:

[a, ., b, .., .., c]

Upvotes: 1

Hakan Dilek
Hakan Dilek

Reputation: 2256

You can filter empty strings out after your split code: 

List<String> stringsList = Stream.of(strings)
      .filter(s -> s.length() > 0)
      .collect(Collectors.toList());

Upvotes: 1

dave
dave

Reputation: 11975

From the Java API:

When there is a positive-width match at the beginning of the input sequence then an empty leading substring is included at the beginning of the resulting array.

In your case the match to the initial / means an empty string is the first result. You can think of it as what comes before the separator.

Upvotes: 2

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