CODEWITHSUNDEEP
xmlxslt
chewflow
chewflow

Reputation: 81

Use if statement in 1 XSLT file to transform 2 different types of XML files

I'm trying to use a single XSLT file to transform 2 (or more) different types of XML files.

I was hoping there would be some way to perform a check for the type of XML file by checking its "id" value and then run the corresponding transformation.

For example,

XML file 1:

<?xml version='1.0' ?>
<file1 id="123">
	<key>
            <uuid>123456</uuid>
	</key>
</file1>

XML file 2:

<?xml version='1.0' ?>
<file2 id="456">
    <house>
        <doors>1</doors>
        <windows>4</windows>
    </house>
</file2>

XSLT file:

<?xml version="1.0" encoding="UTF-8"?> 
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> 
<xsl:template match="/"> 


<html> 
<body> 
    <xsl:choose>

        <xsl:when test="@id = 123">
        // do something
        </xsl:when>
    
        <xsl:when test="@id = 456">
        // do something else
        </xsl:when>
    
        <xsl:otherwise>
        // exception message
        </xsl:otherwise>
    
    </xsl:choose>
</body> 
</html> 
</xsl:template> 
</xsl:stylesheet>

The XML files will all have the same "id" in their root but I can't figure out how to query the root for the "id" value?

Upvotes: 0

Views: 70

Answers (1)

markusk
markusk

Reputation: 6677

To fetch an attribute on the root element (regardless what the root element is), use /*/@id.

<xsl:choose>

    <xsl:when test="/*/@id = 123">
        // do something
    </xsl:when>

    <xsl:when test="/*/@id = 456">
        // do something else
    </xsl:when>

    <xsl:otherwise>
        // exception message
    </xsl:otherwise>

</xsl:choose>

Upvotes: 1

Related Questions